【发布时间】:2018-07-06 16:40:11
【问题描述】:
我有 php 代码,它从 words 表中获取 names of toys,并使用布尔模式全文搜索在 toys 表的 toys_text 字段中匹配这些单词,并显示 names of toys 的 users 和 counts网页上的玩具和唯一身份用户。
玩具名称可以是一个单词,也可以是单词的组合。我们想从toys 中获取这些结果,其中toys_text 字段包含words 表中单词组合的所有单词
(例如 - 如果 words 表有名为 blue car 的条目 - blue 和 car 都应该出现在 toys 表 toys_text 字段中以进行匹配)。数据库随着时间的推移而变化,新玩具的用户被添加,而过时的玩具则用户被删除。
我在将数组正确转换为字符串以输入到布尔全文搜索时遇到问题。我使用foreach 循环并希望输出 +(blue) +(car) 但它只是将 +(car) 插入到布尔全文查询中。
echo $query1 输出
`select COUNT(*) as 'count', COUNT(DISTINCT tw.screen_name) AS 'cnt' from
tweets tw join users us on tw.user_id=us.user_id WHERE MATCH (tweet_text)
AGAINST (' +(car)' IN BOOLEAN MODE)`
虽然我希望查询输出为
`select COUNT(*) as 'count', COUNT(DISTINCT tw.screen_name) AS 'cnt' from
tweets tw join users us on tw.user_id=us.user_id WHERE MATCH (tweet_text)
AGAINST ('+(blue) +(car)' IN BOOLEAN MODE)`
这是我的代码 -
<?php
$query = "SELECT * FROM words ORDER BY `words`.`words`
ASC";
$result = mysqli_query($con, $query);
$i = 1;
while($row = mysqli_fetch_array($result)){
$Word = $row['words'];
$WordsArr = explode(" ", $row['words']);
$query = "";
if(count($WordsArr) > 1){
foreach ($WordsArr as $value) {
$value1 = " +"."(".$value."*".")";
}
$query1 = "select COUNT(*) as 'count', COUNT(DISTINCT
t.name) AS 'cnt' from toys t WHERE MATCH (toys_text) AGAINST
('$value1' IN BOOLEAN MODE)";
}else{
$query1 = "select COUNT(*) as 'count', COUNT(DISTINCT t.name) AS
'cnt' from toys t WHERE
MATCH (toys_text) AGAINST ('$WordsArr[0]* IN BOOLEAN MODE')";
}
$Data1 = mysqli_query($con, $query1);
$total1 = mysqli_fetch_assoc($Data1);
?>
<tr>
<td><?php echo $i;?></td>
<td><?php echo $row['words'];?></td>
<td><a href="showtoys.php?word=<?php echo
urlencode($Word); ?>" target="_blank"><?php echo
$total1['count']; ?></a></td>
<td><a href="showtoys.php?keyword=<?php echo urlencode($Word);
?>" target="_blank"><?php echo $total1['cnt']; ?></a></td>
</tr>
<?php $i++;} ?>
【问题讨论】:
标签: php mysql full-text-search