Jmeter：JSON 响应操作并传递给下一个 http 请求

Question

我已经从 HTTP GET 请求中获得了 JSON 文件的响应，我想使用该 JSON 并将其传递给下一个 HTTP 请求。我得到了以下响应数据

{
  "apiInfo": {
      "id": "23143",
      "name": "bookkeeping",
      "state": "used",
      "data": "15893712000000"
  },
  "apiDetails": [
     {
        "bookName": "abc",
        "state": "old",
        "noOfTimesUsed": "53"
        "additionalParam"{
            "name": "abc",
            "id": "123"
        }
    },
    {
        "bookName": "def",
        "state": "new",
        "noOfTimesUsed": "5",
        "action": "keep"
        "additionalParam"{
            "name": "def",
            "id": "456"
        }
    },
    {
        "bookName": "xyz",
        "state": "avg",
        "noOfTimesUsed": "23"
        "additionalParam"{
            "name": "ghi",
            "id": "789"
        }
    },
    {
        "bookName": "pqr",
        "state": "old",
        "noOfTimesUsed": "75",
        "action": "discard"
        "additionalParam"{
            "name": "jkl",
            "id": "012"
        }
    }
  ]
}

我想使用 JSON 响应中的“apiInfo”和“apiDetails”部分并操作其数据。如您所见，某些数组字段中包含属性“action”，而有些则没有。我想确保数组中的所有字段都有这些数据并被分配为'“action”：“keep”'。另外，我想添加来自 apiInfo 的“id”和来自 apiDetails 本身的附加参数的“名称”。我想要的最终结果有点像这样

"apiDetails": [
   {
      "id": "23143",
      "bookName": "abc",
      "state": "old",
      "noOfTimesUsed": "53",
      "action": "keep",
      "name":"abc"
   },
   {
       "id": "23143",
       "bookName": "def",
       "state": "new",
       "noOfTimesUsed": "5",
       "action": "keep",
      "name":"def"
   },
   { 
       "id": "23143",
       "bookName": "xyz",
       "state": "avg",
       "noOfTimesUsed": "23",
       "action": "keep",
      "name":"ghi"
   },
   {
       "id": "23143",
       "bookName": "pqr",
       "state": "old",
       "noOfTimesUsed": "75",
       "action": "keep",
      "name":"jkl"
    }
  ]

我一直在尝试使用 JSR223 采样器并且一直在苦苦挣扎。这有点复杂，我需要帮助。 P.S.：我尝试使用 javascript 代码来根据需要操纵结果，但没有成功。

请帮忙。

谢谢，席德

Answer 1

1. 将JSR223 PostProcessor 添加为返回上述 JSON 的请求的子项

2. 将以下代码放入“脚本”区域：

   def apiDetails = new groovy.json.JsonSlurper().parse(prev.getResponseData()).apiDetails
   
   apiDetails.each { apiDetail ->
       apiDetail.put('action', 'keep')
   }
   
   vars.put('request', new groovy.json.JsonBuilder(apidetails: apiDetails.collect()).toPrettyString())
   

3. 就是这样，您应该可以在需要的地方将生成的请求称为${request}

更多信息：

• Apache Groovy - Parsing and producing JSON
• Apache Groovy - Why and How You Should Use It