与 ASP.NET 网站和 Web API 移动后端共享 SignalR 集线器

Question

我已经为基于 ASP.NET 的网站设置了 SignalR 实时通信。但是，我需要知道是否可以与处理相同服务器和数据库的单独移动后端项目共享相同的 SignalR 集线器。基本上就像通过网页和手机同时访问facebook的收件箱一样？

这将是一个 ASP.NET Web 项目和一个连接到一个集线器的移动客户端。

Answer 1

如果您想找到 SignalR for Android，我建议您从以下工作链接开始

• SignalR/java-client at GitHub

您可以参考以下示例代码（这是我在 SO 关于 SignalR for Android 的问题：SignalR for Android: how can I pass dynamic class to SubscriptionHandler1

public <T> void startSignalR(String transport, String serverUrl, final String userName, final Class<T> tClass) {

    Platform.loadPlatformComponent(new AndroidPlatformComponent());
    Credentials credentials = new Credentials() {
        @Override
        public void prepareRequest(Request request) {
            request.addHeader(HEADER_KEY_USERNAME, userName);
        }
    };

    mConnection = new HubConnection(serverUrl);
    mConnection.setCredentials(credentials);
    mHub = mConnection.createHubProxy(SERVER_HUB_CHAT);

    if (transport.equals("ServerSentEvents")) {
         mTransport = new ServerSentEventsTransport(mConnection.getLogger());
    } else if (transport.equals("LongPolling")) {
         mTransport = new LongPollingTransport(mConnection.getLogger());
    }

    mAwaitConnection = mConnection.start(mTransport);

    try {
        mAwaitConnection.get();
    } catch (InterruptedException e) {      
        e.printStackTrace();      
        return;
    } catch (ExecutionException e) { 
        e.printStackTrace();
        return;
    }

    mHub.on("broadcastMessage",
            new SubscriptionHandler1<Object>() {
                @Override
                public void run(final Object msg) {
                    final String finalMsg;
                    Gson gson = new Gson();
                    Object object = gson.fromJson(msg.toString(), tClass);
                    Field[] fields = object.getClass().getDeclaredFields();
                    for (int i = 0; i < fields.length; i++) {
                        try {
                            System.out.println("Value = " + fields[i].get(object));                                
                        } catch (Exception e) {
                            e.printStackTrace();
                        }
                    }                        
                }
            }
            , Object.class);

    ...
}

希望这会有所帮助！