如何在不使用第三方 url 的情况下获取 iPhone 的公共 IP 地址

Question

对于我的项目，我需要获取 iPhone 的公共 IP 地址，有很多可用的示例，通过使用外部/第三方 URL 显示公共 IP 地址。我只想知道如何在不使用另一个 url 的帮助下提取 iPhone 的 IP 地址。

注意：- 我用了这个但只显示本地IP地址，我需要公共IP地址

   func getIPAddress() -> [String] {
    var addresses = [String]()

    // Get list of all interfaces on the local machine:
    var ifaddr : UnsafeMutablePointer<ifaddrs> = nil
    if getifaddrs(&ifaddr) == 0 {

        // For each interface ...
        for (var ptr = ifaddr; ptr != nil; ptr = ptr.memory.ifa_next) {
            let flags = Int32(ptr.memory.ifa_flags)
            var addr = ptr.memory.ifa_addr.memory

            // Check for running IPv4, IPv6 interfaces. Skip the loopback interface.
            if (flags & (IFF_UP|IFF_RUNNING|IFF_LOOPBACK)) == (IFF_UP|IFF_RUNNING) {
                if addr.sa_family == UInt8(AF_INET) || addr.sa_family == UInt8(AF_INET6) {

                    // Convert interface address to a human readable string:
                    var hostname = [CChar](count: Int(NI_MAXHOST), repeatedValue: 0)
                    if (getnameinfo(&addr, socklen_t(addr.sa_len), &hostname, socklen_t(hostname.count),
                        nil, socklen_t(0), NI_NUMERICHOST) == 0) {
                            if let address = String.fromCString(hostname) {
                                addresses.append(address)
                            }
                    }
                }
            }
        }
        freeifaddrs(ifaddr)
    }

    return addresses
}

我在我的swift项目中使用了这个头文件，它会生成本地IP

Answer 1

import Darwin

var hostName = [Int8](count: 255, repeatedValue: 0)
gethostname(&hostName, hostName.count)

var hints = addrinfo()
var res = UnsafeMutablePointer<addrinfo>()
var p = UnsafeMutablePointer<addrinfo>()
var p4 = UnsafeMutablePointer<sockaddr_in>()
var p6 = UnsafeMutablePointer<sockaddr_in6>()

hints.ai_flags = AI_ALL
hints.ai_family = PF_UNSPEC
hints.ai_socktype = SOCK_STREAM
var ipstr = [CChar](count: Int(INET6_ADDRSTRLEN), repeatedValue: 0)

print("List of IP addresses on host \(String.fromCString(hostName)!)\n")

if getaddrinfo( hostName, "0", &hints, &res) == 0 {

    var ipFamily = ""
    var s: Int32 = 0
    var port: in_port_t = 0
    for(p = res; p != nil; p = p.memory.ai_next) {

        switch p.memory.ai_family {
        case PF_INET:
            p4 = UnsafeMutablePointer<sockaddr_in>(p.memory.ai_addr)
            inet_ntop(AF_INET, &p4.memory.sin_addr, &ipstr, socklen_t(INET6_ADDRSTRLEN))
            ipFamily = "IPv4"
            port = p4.memory.sin_port.bigEndian
        case PF_INET6:
            p6 = UnsafeMutablePointer<sockaddr_in6>(p.memory.ai_addr)
            inet_ntop(AF_INET6, &p6.memory.sin6_addr, &ipstr, socklen_t(INET6_ADDRSTRLEN))
            ipFamily = "IPv6"
            port = p6.memory.sin6_port.bigEndian
        default:

            break
        }
        print("\t\(ipFamily):", String.fromCString(ipstr)!)

    }
    // free unmanaged memmory !!!!!
    freeaddrinfo(res)
}

在我自己的电脑上打印

List of IP addresses on host Ivos-MacBook.local

    IPv6: fe80::225:ff:fe40:9c72
    IPv6: 2a02:130:200:1350:225:ff:fe40:9c72
    IPv4: 192.168.1.106

对于外部 IP，您需要外部服务的帮助（不是 swift 特定的 :-)）

Answer 2

let address = try? String(contentsOf: URL(string: "https://api.ipify.org")!, encoding: .utf8)
print(address)

然后你得到公共 IP 地址