Django-Rest 获取相关子列表的 URL

Question

我得到了一个与 django contrib auth User 模型相关的简单模型。我想为公司创建一个 CRUD，但将相关元素设置为列表的 url 而不是元素列表（即指向员工列表的链接而不是单个员工的 url 列表）。这里缺少什么？

models.py

from django.db import models
from django.contrib.auth import get_user_model
User = get_user_model()

class Company(models.Model):
    name = models.CharField(max_lenght=256)
    employees = models.ManyToManyField(User)

序列化器.py

from rest_framework import serializers
from django.contrib.auth import get_user_model
User = get_user_model()

from .models import Company

class CompanySerializer(serializers.HyperlinkedModelSerializers):

    class Meta:
        model = Company
        fields = ('name', 'employees')

class UserSerializer(serializers.ModelSerializers):

    class Meta:
        model = User
        fields = ('username', 'password', 'email') # and so on

view.py

from rest_framework import viewsets
from django.contrib.auth import get_user_model
User = get_user_model()
from .models import Company

from .serializers import UserSerializer, CompanySerializer

class UserViewset(viewsets.ModelViewSet):
    serializer_class = UserSerializer
    queryset = User.objects.all()

class CompanyViewset(viewsets.ModelViewSet):
    serializer_class = CompanySerializer
    queryset = Company.objects.all()

urls.py

from django conf.urls import url, include
from rest_framework.routers import DefaultRouter
from .views import CompanyViewSet, UserViewSet
router = DefaultRouter()
router.register(r'company', CompanyViewSet)
router.register(r'users', UserViewSet)

urlpatterns = [url(r^api/, include(router.urls))]

Answer 1

听起来您正在寻找Hyperlinked Identity Field。对你来说，它可能看起来像这样：

class CompanySerializer(serializers.HyperlinkedModelSerializers):
    employee_listing = serializers.HyperlinkedIdentityField(view_name='employee-list')

    class Meta:
        model = Company
        fields = ('name', 'employee_listing')