【问题标题】:Adjust threshold cros_val_score sklearn调整阈值 cros_val_score sklearn
【发布时间】:2020-09-09 22:11:18
【问题描述】:

有没有办法设置阈值cross_val_score sklearn?

我已经训练了一个模型,然后我将阈值调整为 0.22。模型如下:

# Try with Threshold
pred_proba = LGBM_Model.predict_proba(X_test)


# Adjust threshold for predictions proba
prediction_with_threshold = []
for item in pred_proba[:,0]:
    if item > 0.22 :
        prediction_with_threshold.append(0)
    else:
        prediction_with_threshold.append(1)

print(classification_report(y_test,prediction_with_threshold))

然后我想使用 cross_val_score 验证这个模型。我已经搜索但找不到为 cross_val_score 设置阈值的方法。我使用的 cross_val_score 如下所示:

F1Scores = cross_val_score(LGBMClassifier(random_state=101,learning_rate=0.01,max_depth=-1,min_data_in_leaf=60,num_iterations=200,num_leaves=70),X,y,cv=5,scoring='f1')
F1Scores

### how to adjust threshold to 0.22 ??

或者还有其他方法可以使用阈值来验证这个模型?

【问题讨论】:

    标签: python machine-learning scikit-learn cross-validation


    【解决方案1】:

    假设您正在处理一个二分类问题,您可以使用如下所示的阈值方法覆盖 LGBMClassifier 对象的 predict 方法:

    import numpy as np
    from lightgbm import LGBMClassifier
    from sklearn.datasets import make_classification
    
    X, y = make_classification(n_features=10, random_state=0, n_classes=2, n_samples=1000, n_informative=8)
    
    class MyLGBClassifier(LGBMClassifier):
        def predict(self,X, threshold=0.22,raw_score=False, num_iteration=None,
                    pred_leaf=False, pred_contrib=False, **kwargs):
            result = super(MyLGBClassifier, self).predict_proba(X, raw_score, num_iteration,
                                        pred_leaf, pred_contrib, **kwargs)
            predictions = [1 if p>threshold else 0 for p in result[:,0]]
            return predictions
    
    clf = MyLGBClassifier()
    clf.fit(X,y)
    clf.predict(X,threshold=2)  # just testing the implementation
    # [0,0,0,0,..,0,0,0]        # we get all zeros since we have set threshold as 2
    
    F1Scores = cross_val_score(MyLGBClassifier(random_state=101,learning_rate=0.01,max_depth=-1,min_data_in_leaf=60,num_iterations=2,num_leaves=5),X,y,cv=5,scoring='f1')
    F1Scores
    #array([0.84263959, 0.83333333, 0.8       , 0.78787879, 0.87684729])
    

    希望这会有所帮助!

    【讨论】:

    • 我曾尝试使用 KFold 分离数据,然后尝试使用循环一一预测.. 但我认为它更有效。我会试试这个。感谢您的帮助
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