Python Beautiful Soup 在包含字符串的多行 <p> 中打印特定行

Question

如何在一个包含特定字符串的<p> 标记中仅获取/打印大的多行文本的行？在网站上，这些行是用<br> 标签实现的。没有关闭 </p> 标记。

网站的基本结构：

<p style="line-height: 150%">
I need a big cup of coffee and cookies.
<br>
I do not like tea with milk.
<br>
I can't live without coffee and cookies.
<br>
...

假设我只想获取/打印包含“咖啡和饼干”字样的行。因此，在这种情况下，应该只打印此<p> 的第一和第三“行”/ 句子。

我在 Python 3.7.1 下安装了 Beautiful Soup 4.6.3。

findAll 似乎是面向标签的并返回整​​个<p>，对吗？那我怎么能意识到呢？也许使用正则表达式或其他模式？

Answer 1

如果我能正确理解您的要求，那么以下 sn-p 应该可以帮助您：

from bs4 import BeautifulSoup

htmlelem = """
    <p style="line-height: 150%">
    I need a big cup of coffee and cookies.
    <br>
    I do not like tea with milk.
    <br>
    I can't live without coffee and cookies.
    <br>
"""

soup = BeautifulSoup(htmlelem, 'html.parser')
for paragraph in soup.find_all('p'):
    if not "coffee and cookies" in paragraph.text:continue
    print(paragraph.get_text(strip=True))

Answer 2

你能在 \n 上拆分吗？

from bs4 import BeautifulSoup

html = """
    <p style="line-height: 150%">
    I need a big cup of coffee and cookies.
    <br>
    I do not like tea with milk.
    <br>
    I can't live without coffee and cookies.
    <br>
"""

soup = BeautifulSoup(html, 'html.parser')
for item in soup.select('p'):
    r1 = item.text.split('\n')
    for nextItem in r1:
        if "coffee and cookies" in nextItem:
            print(nextItem)

Answer 3

使用str() 将bs4.element 转换为字符串，然后您可以将其与“咖啡和饼干”进行比较

from bs4 import BeautifulSoup

html_doc = """<p style="line-height: 150%">
    I need a big cup of coffee and cookies. <a href="aaa">aa</a>
    <br>
    I do not like tea with milk.
    <br>
    I can't live without coffee and cookies.
    <br>"""

soup = BeautifulSoup(html_doc, 'html.parser')
paragraph = soup.find('p')

for p in paragraph:
  if 'coffee and cookies' in str(p):
    next_is_a = p.find_next_sibling('a')
    if next_is_a:
      print(p.strip() + ' ' + str(next_is_a))
    else:
      print(p.strip())