从 Instagram 下载图像时出错答案

【问题标题】：Error While downloading image from instagram从 Instagram 下载图像时出错
【发布时间】：2021-06-12 01:56:25
【问题描述】：

大家好，我的方案无效，这段代码有很多错误

我只是想从给定的 url 制作一个简单的 instagram 图片下载器这是代码

import requests
from bs4 import BeautifulSoup

def get_response(url):
    r = requests.get(url)
    while not r.ok:
        return r.status_code
    return r.text

url = input('Enter Instagram URL: ')
response = get_response(url)

soup = BeautifulSoup(response,"lxml")

image = soup.find("meta", property="og:image")
image = str(image)
image = image.replace("amp;","")
print(image)                    ### Here is working fine when you click printed link it works 

r = requests.get(image)         ### Problem is at here
with open('cat3.jpg', 'wb') as f:
   f.write(r.content)

# https://www.instagram.com/p/CL1TxMRlhe7/ #sample cat image

此处列出的错误

Traceback (most recent call last):

  File "D:\Python öğreniyorum\ana_dosya.py", line 20, in <module>
    r = requests.get(image)         ### Problem is at here

  File "C:\Users\Pc\AppData\Local\Programs\Python\Python39\lib\site-packages\requests\api.py", line 76, in get
    return request('get', url, params=params, **kwargs)

  File "C:\Users\Pc\AppData\Local\Programs\Python\Python39\lib\site-packages\requests\api.py", line 61, in request
    return session.request(method=method, url=url, **kwargs)
  File "C:\Users\Pc\AppData\Local\Programs\Python\Python39\lib\site-packages\requests\sessions.py", line 542, in request
    resp = self.send(prep, **send_kwargs)

  File "C:\Users\Pc\AppData\Local\Programs\Python\Python39\lib\site-packages\requests\sessions.py", line 649, in send
    adapter = self.get_adapter(url=request.url)

  File "C:\Users\Pc\AppData\Local\Programs\Python\Python39\lib\site-packages\requests\sessions.py", line 742, in get_adapter
    raise InvalidSchema("No connection adapters were found for {!r}".format(url))
requests.exceptions.InvalidSchema: No connection adapters were found for '<meta content="https://instagram.fsaw3-1.fna.fbcdn.net/v/t51.2885-15/e35/s1080x1080/155344637_426370308591690_7809000723152066300_n.jpg?tp=1&_nc_ht=instagram.fsaw3-1.fna.fbcdn.net&_nc_cat=106&_nc_ohc=sP6bYsFdL_0AX8yIuXZ&oh=a7e381762b429e6c7b3b494b510ca166&oe=60790CBF" property="og:image"/>'

【问题讨论】：

如错误消息的最后一行所示，您正尝试向无效的 URL 发送请求。它是无效的，因为它包含 HTML 标记 meta。您必须获取 HTML 代码的 content 属性中的 URL。
谢谢我解决了 :) 我做了一个快速修复，比如 image = image[15:-23] 并获得了纯 url 链接，它工作了，我稍后会用 re sub 来做 :) 谢谢跨度>
我已经为您的问题发布了一个比您提出的更可靠的正确答案。如果有效，请点击复选标记。

标签： python beautifulsoup python-requests urllib

【解决方案1】：

如错误消息的最后一行所示，您正在尝试向无效的 URL 发送请求。它是无效的，因为它包含 HTML 标记 meta。您必须获取 HTML 代码的 content 属性中的 URL。

这是获取 Instagram 图片 URL 所需的代码：

image = soup.find("meta", property="og:image")["content"]

【讨论】：

【解决方案2】：

谢谢大家我解决了快速修复是修剪图像字符串中的元内容和 og 属性文本，它起作用了

【讨论】：