【发布时间】:2021-04-17 23:10:49
【问题描述】:
假设我有这个模型:
def mask_layer(tensor):
return layers.Multiply()([tensor, tf.ones([1, 128])])
def get_model():
inp_1 = keras.Input(shape=(64, 101, 1), name="input")
x = layers.Conv2D(256, kernel_size=(3, 3), kernel_regularizer=l2(1e-6), strides=(3, 3), padding="same")(inp_1)
x = layers.LeakyReLU(alpha=0.3)(x)
x = layers.Conv2D(128, kernel_size=(3, 3), kernel_regularizer=l2(1e-6), strides=(3, 3), padding="same")(x)
x = layers.LeakyReLU(alpha=0.3)(x)
x = layers.Flatten()(x)
x = layers.Dense(512)(x)
x = layers.LeakyReLU(alpha=0.3)(x)
x = layers.Dense(256)(x)
x = layers.LeakyReLU(alpha=0.3)(x)
x= layers.Dense(128, name="output1")(x)
mask = layers.Lambda(mask_layer, name="lambda_layer")(x)
out2 = layers.Dense(40000, name="output2")(mask)
model = keras.Model(inp_1, [mask, output2], name="2_out_model")
model.compile(optimizer=tf.keras.optimizers.Adam(learning_rate=0.001),
loss="mean_squared_error")
plot_model(model, to_file='model.png', show_shapes=True, show_layer_names=True)
model.summary()
return model
然后,我训练我的网络:
model = get_model()
es = tf.keras.callbacks.EarlyStopping(monitor='val_loss', mode='min', verbose=1, patience=50)
history = model.fit(X_train, [Y_train, Z_train], validation_data=(X_val, [Y_val, Z_val]), epochs=500,
batch_size=32,
callbacks=[es])
test_loss, _, _ = model.evaluate(X_test, [Y_test, Z_test], verbose=1)
我想用另一个训练集重新训练已经训练过的网络,但是改变了 Lambda 层的定义,假设这次函数返回:
return layers.Multiply()([tensor, tf.ones([1, 128])*1.2])
我是否需要调用函数“get_model()”(因为我重新定义了一个层)然后再次拟合?不存在重新初始化模型权重的风险吗?提前谢谢你:)
【问题讨论】:
标签: python tensorflow machine-learning keras deep-learning