如何删除一段 HTML 周围的封闭标签？

Question

我正在使用 customfilter 模块为 Drupal 使用 asciidoc 语法为文本创建自定义过滤器。我将它包含在 [asciidoc][/asciidoc] 标签中，当我通过 asciidoctor 命令运行它时，输出包含在 <div class="paragraph"><p> 标签中。

我使用 [asciidoc] 标签格式化 html 链接的输出是这样的。

On the markup side Drupal's contrib `markdown` filter has been somewhat iffy,
and so has the `bbcode` filter. Looking around for other more compact documenting
systems led me to the https://asciidoc.org[Asciidoc] utility and its more
advanced brother https://asciidoctor.org[Asciidoctor]. In combination with another
 Drupal module called https://drupal.org/project/customfilter[customfilter] which
makes it easy to create your own filters, I think I have hit on a combination
of modules which allow me as much freedom and fine control on my pages as I want.

<div class="paragraph">
<p>On the markup side Drupal&#8217;s contrib <code>markdown</code> filter has been somewhat iffy,
and so has the <code>bbcode</code> filter. Looking around for other more compact documenting
systems led me to the <a href="https://asciidoc.org">Asciidoc</a> utility and its more
advanced brother <a href="https://asciidoctor.org">Asciidoctor</a>. In combination with another
 Drupal module called <a href="https://drupal.org/project/customfilter">customfilter</a> which
makes it easy to create your own filters, I think I have hit on a combination
of modules which allow me as much freedom and fine control on my pages as I want.</p>
</div>

是否有一些 PHP 函数可以将字符串 HTML 和一组封闭标签转换为字符串，并返回它们所包含的内部 HTML？或者也许是一些可以匹配标签之间部分的正则表达式？

这是想要的输出

On the markup side Drupal&#8217;s contrib <code>markdown</code> filter has been somewhat iffy,
and so has the <code>bbcode</code> filter. Looking around for other more compact documenting
systems led me to the <a href="https://asciidoc.org">Asciidoc</a> utility and its more
advanced brother <a href="https://asciidoctor.org">Asciidoctor</a>. In combination with another
 Drupal module called <a href="https://drupal.org/project/customfilter">customfilter</a> which
makes it easy to create your own filters, I think I have hit on a combination
of modules which allow me as much freedom and fine control on my pages as I want.

我问了一个相关问题，是否可以配置 asciidoc 以避免将输出包含在 <div class="paragraph"><p>...</p></div> - Does asciidoctor have a setting to remove the <paragraph> and <p> tags from the source it outputs? 中

Answer 1

通过纯 PHP，您可以使用 DOMDocument，我不建议您使用它，因为它很慢，而且您在跟踪它的错误时会遇到麻烦等等。出于同样的原因，我不会解释更多关于该对象的信息。只是来自官方网站的链接：

PHP DomDocument

注意：当您处理大文本时，我个人更喜欢使用DomDocument，例如，我曾经阅读整个页面并一一获取所有元素，这几乎不可能使用正则表达式。在那种情况下，我使用了DomDocument。

让我们回到你的主题。您的示例表明您没有解析大块，因此我建议使用Regex。

preg_match_all( '/<p>(?P<content>.*?)<\/p>/s' ,$text, $ref );
var_dump($ref['content']);

上面的正则表达式给你所有的元素 beetwen p 标签。

您可以像这样玩它并制作一个新的：

preg_match_all( '/<div class="paragraph">\s<p>(?P<content>.*?)<\/*p>\s<\/*div>/' ,$text, $ref );

它为您提供 div 标签之间的所有内容（标签可能具有任何属性）。

另请参阅下面的正则表达式链接

Regex Tutorial

祝你好运