【发布时间】:2023-03-13 08:02:01
【问题描述】:
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我有什么
我在 Flask 中有一个客户端/服务器。客户端向服务器发送 JSON 格式的查询,服务器创建一个 JSON 文件。还有另一个工具接受这个查询,在数据库上执行它并将结果写入 results.txt 文件。服务器定期检查 'results' 目录中的 .txt 文件,如果找到新文件,则提取结果。对于定期检查部分,我使用了 APS。
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我想做的事 现在我想将服务器从 .txt 文件中提取的数据(queryResult)发送回客户端。
这是我到目前为止所做的。
- 服务器代码:
app = Flask(__name__) api = Api(app) # Variable to store the result file count in the Tool directory fileCount = 0 # Variable to store the query result generated by the Tool queryResult = 0 # Method to read .txt files generated by the Tool def readFile(): global fileCount global queryResult # Path where .txt files are created by the Tool path = "<path>" tempFileCount = len(fnmatch.filter(os.listdir(path), '*.txt')) if (fileCount != tempFileCount): fileCount = tempFileCount list_of_files = glob.iglob(path + '*.txt') latest_file = max(list_of_files, key=os.path.getctime) print("\nLast modified file: " + latest_file) with open(latest_file, "r") as myfile: queryResult = myfile.readlines() print(queryResult) # I would like to return this queryResult to the client scheduler = BackgroundScheduler() scheduler.add_job(func=readFile, trigger="interval", seconds=10) scheduler.start() # Shut down the scheduler when exiting the app atexit.register(lambda: scheduler.shutdown()) # Method to write url parameters in JSON to a file def write_file(response): time_stamp = str(time.strftime("%Y-%m-%d_%H-%M-%S")) with open('data' + time_stamp + '.json', 'w') as outfile: json.dump(response, outfile) print("JSON File created!") class GetParams(Resource): def get(self): response = json.loads(list(dict(request.args).keys())[0]) write_file(response) api.add_resource(GetParams, '/data') # Route for GetJSON() if __name__ == '__main__': app.run(port='5890', threaded=True)
- 客户代码
data = { 'query': 'SELECT * FROM table_name' } url = 'http://127.0.0.1:5890/data' session = requests.Session() retry = Retry(connect=3, backoff_factor=0.5) adapter = HTTPAdapter(max_retries=retry) session.mount('http://', adapter) session.mount('https://', adapter) resp = session.get(url, params=json.dumps(data)) print(resp)
任何人都可以帮助我如何将此查询结果发送回客户端吗?
编辑:我希望服务器每次在 Tool 目录中遇到新文件时都将 queryResult 发送回客户端,即每次找到新文件时,它都会提取结果(它目前正在执行此操作)并将其发送回客户端。
【问题讨论】:
标签: python json rest flask client-server