将逻辑字符串转换为 JSON

Question

我想转换自：

输入：

"#serviceRequest and @charges:getRoamingCharges or @plans:dataplans"

'#' - 意图 '@' - 实体 ':'-值

输出：

{"and":[
{"some" : [ {"var":"intents"}, {"==":[{"var":"intent"}]}, 
"serviceRequest"]},
{"or":[
{"and":[{"some" : [ {"var":"entities"}, {"==":[{"var":"entity"}, 
"charges"]} ]},
{"some" : [ {"var":"entities"}, {"==":[{"var":"value"}, 
"getRoamingCharges"]} ]}]
},{"and":[
{"some" : [ {"var":"entities"}, {"==":[{"var":"entity"}, "plans"]} 
]},
{"some" : [ {"var":"entities"}, {"==":[{"var":"value"}, "data 
plans"]} ]}
]}
]}
]}

我尝试过的：

import pyparsing

identifier = pyparsing.QuotedString('"')
operator = (
    pyparsing.Literal("==") |
    pyparsing.Literal("≠") |
    pyparsing.Literal("≥") |
    pyparsing.Literal("≤") |
    pyparsing.Literal("<") |
    pyparsing.Literal(">")
)
value = pyparsing.QuotedString('"')

match_format = identifier + operator + value

  #print(match_format.parseString('"foobar"=="123"'))
  def list_to_dict(pos, tokens):
    dic = {}
    lis =[]
   print(tokens)
  abc= {tokens[1]: {tokens[2], tokens[0]}}
print(abc)
lis.append(abc)
dic['bfeh']=lis
return tokens


 match_format = (identifier + operator + 
  value).setParseAction(list_to_dict)

 print(match_format.parseString('"intent"=="serviceRequest"'))

给：

{'==': {'intent', 'serviceRequest'}}

请帮助我使用 Parsing (Python) 或任何您想要的替代方法？

Answer 1

您可以创建一个更简单的标记器来与解析器链接：

import re
class Token:
  grammar, _types = r'and|or|#|:|@|\w+', [('and', 'cond'), ('or', 'cond'), ('#', 'intent'), ('@', 'entity'), (':', 'value'), (r'\w+', 'label')]
  def __init__(self, val, _type):
     self.val, self._type = val, _type
  @property
  def is_cond(self):
     return self._type == 'cond'
  @property
  def is_desc(self):
     return self._type in {'intent', 'entity', 'value'}
  @property
  def var_name(self):
     return f'{self._type}s' if self._type == 'intent' else 'entities'
  @classmethod
  def tokenize(cls, _input):
     return [cls(i, [b for a, b in cls._types if re.findall(a, i)][0]) for i in re.findall(cls.grammar, _input)]
  def __repr__(self):
     return f'{self.__class__.__name__}(value={self.val}, type={self._type})'

现在，可以创建一个简单的解析器：

from itertools import groupby
class AST:
   def __init__(self, stream):
      self.stream = iter(stream)
   def p_parse(self, stream):
      _r, _id, _name = [], None, ''
      for i in stream:
         if i._type == 'value':
            if _name:
               _r.append([{'var':_id.var_name if _id is not None else 'entities'}, {"==":[{"var":'value' if _id is None else _id._type}, _name]}])
            _id, _name = None, ''
         elif i.is_desc:
            _id = i
         else:
            _name = i.val
            _r.append([{'var':i.var_name if _id is not None else 'entities'}, {"==":[{"var":'value' if _id is None else _id._type}, _name]}])
            _id, _name = None, ''
      return {'some':_r[0]} if len(_r) == 1 else {'and':[{'some':_r[0]}, {'some':_r[1]}]}
   def parse(self, seen=None):
      a, b = next(self.stream, [None, None])
      if a is not None:
         return self.parse(self.p_parse(b)) if not a else {b[0].val:[seen,  self.parse()]}
      return seen
   @classmethod
   def _group(cls, _tokens):
     return cls([(a, list(b)) for a, b in groupby(_tokens, key=lambda x:x.is_cond)])

现在，组合组件：

s = "#serviceRequest and @charges:getRoamingCharges or @plans:dataplans"
result = AST._group(Token.tokenize(s)).parse()

输出：

{'and': [{'some': [{'var': 'entities'}, {'==': [{'var': 'intent'}, 'serviceRequest']}]}, {'or': [{'and': [{'some': [{'var': 'entities'}, {'==': [{'var': 'entity'}, 'charges']}]}, {'some': [{'var': 'entities'}, {'==': [{'var': 'value'}, 'getRoamingCharges']}]}]}, {'and': [{'some': [{'var': 'entities'}, {'==': [{'var': 'entity'}, 'plans']}]}, {'some': [{'var': 'entities'}, {'==': [{'var': 'value'}, 'dataplans']}]}]}]}]}

毫无疑问，这个问题有更短的解决方案，但是，标记器和解析器的目标是让您在未来更容易扩展这个解决方案，以处理无法被更“hackish”处理的输入解决方案。