Python 请求使用 ast.literal_eval 错误语法无效？

Question

我是 python 新手，尝试使用 ast.literal_eval 获取请求数据导致“无效语法”错误。

它打印我发送的格式如下的数据，

192.156.1.0,8181,database,admin,12345

在 python 中我显示它，但在读取它时出错，我的代码是，

    print str(request.body.read())
    datas = request.body.read()
    data=ast.literal_eval(datas)
    dbname = data['dbname']
    username = data['uname']
    ip = data['ip']
    port = data['port']
    pwd = data['pwd']

data=ast.literal_eval(datas)

行出现无效语法错误

如何解决它的建议将是可观的

谢谢

Answer 1

改变这个：

192.156.1.0,8181,database,admin,12345

到这里：

>>> a = "['192.156.1.0',8181,'database','admin',12345]"
>>> ast.literal_eval(a)
['192.156.1.0', 8181, 'database', 'admin', 12345]

ast.literal_eval

ast.literal_eval(node_or_string)

Safely evaluate an expression node or a Unicode or Latin-1 encoded string containing
a Python literal or container display. The string or node provided may only consist of 
the following Python literal structures: strings, numbers, tuples, lists, dicts, booleans, and None.

 This can be used for safely evaluating strings containing Python values from untrusted 
sources without the need to parse the values oneself. It is not capable of evaluating 

任意复杂的表达式，例如涉及运算符或索引。

你可以这样试试：

>>> a='192.156.1.0,8181,database,admin,12345'
>>> a = str(map(str,a.split(',')))
>>> a
"['192.156.1.0', '8181', 'database', 'admin', '12345']"
>>> ast.literal_eval(a)
['192.156.1.0', '8181', 'database', 'admin', '12345']

您的代码将如下所示：

data=ast.literal_eval(str(map(str,datas.split(','))))

Answer 2

类似的东西呢

dbname, username, ip, port, pwd = request.body.read().split(',')

测试

>>> str = "192.156.1.0,8181,database,admin,12345"
>>> dbname , username , ip, port ,pwd = str.split(',')
>>> dbname
'192.156.1.0'
>>> username
'8181'
>>> ip
'database'
>>> port
'admin'
>>> pwd
'12345'