在 Python 中使用 Selenium 抓取 Google 图片

Question

现在，我一直在尝试使用以下代码抓取 Google 图片：

from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.common.keys import Keys 
import os
import time
import requests
import re
import urllib2
import re
from threading import Thread
import json
#Assuming I have a folder named Pictures1, the images are downloaded there. 
def threaded_func(url,i):
     raw_img = urllib2.urlopen(url).read()
     cntr = len([i for i in os.listdir("Pictures1") if image_type in i]) + 1
     f = open("Pictures1/" + image_type + "_"+ str(total), 'wb')
     f.write(raw_img)
     f.close()
driver = webdriver.Firefox()
driver.get("https://images.google.com/")
elem = driver.find_element_by_xpath('/html/body/div/div[3]/div[3]/form/div[2]/div[2]/div[1]/div[1]/div[3]/div/div/div[2]/div/input[1]')
elem.clear()
elem.send_keys("parrot")
elem.send_keys(Keys.RETURN)
image_type = "parrot_defG"
images=[]
total=0
time.sleep(10)
for a in driver.find_elements_by_class_name('rg_meta'):
     link =json.loads(a.text)["ou"]
     thread = Thread(target = threaded_func, args = (link,total))
     thread.start()
     thread.join()
     total+=1

我尝试使用 Selenium 打开 google 的图像结果页面，然后注意到每个 div 都有类 'rg-meta' 并且后面是 JSON 代码。

我尝试使用 .text 访问它。 JSON 的“ou”索引包含我要下载的图像的来源。我正在尝试使用“rg-meta”类获取所有此类 div 并下载图像。但它显示错误 " NO JSON OBJECT CAN BE DECODED" 我不知道该怎么做。

编辑： 这就是我要说的：

    <div class="rg_meta">{"cl":3,"id":"FqCGaup9noXlMM:","isu":"kids.britannica.com","itg":false,"ity":"jpg","oh":600,"ou":"http://media.web.britannica.com/eb-media/89/89689-004-4C85E0F0.jpg","ow":380,"pt":"grain weevil -- Kids Encyclopedia | Children\u0026#39;s Homework Help ...","rid":"EusB0pk_sLg7vM","ru":"http://kids.britannica.com/comptons/art-143712/grain-or-granary-weevil","s":"grain weevil","sc":1,"st":"Kids Britannica","th":282,"tu":"https://encrypted-tbn2.gstatic.com/images?q\u003dtbn:ANd9GcQPbgXbRVzOicvPfBRtAkLOpJwy_wDQEC6a2q0BuTsUx-s0-h4b","tw":179}</div>

检查 JSON 的“ou”索引。请帮我提取它。

请原谅我的无知。

我通过以下更新解决了这个问题：

    for a in driver.find_elements_by_xpath('//div[@class="rg_meta"]'):
        atext = a.get_attribute('innerHTML')
        link =json.loads(atext)["ou"]
        print link
        thread = Thread(target = threaded_func, args = (link,total))
        thread.start()
        thread.join()
        total+=1

Answer 1

替换：

driver.find_elements_by_class_name('rg_meta') 与driver.find_element_by_xpath('//div[@class="rg_meta"]/text()')

和a.text 和a

将解决您的问题。

结果代码：

from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.common.keys import Keys 
import os
import time
import requests
import re
import urllib2
import re
from threading import Thread
import json
#Assuming I have a folder named Pictures1, the images are downloaded there. 
def threaded_func(url,i):
     raw_img = urllib2.urlopen(url).read()
     cntr = len([i for i in os.listdir("Pictures1") if image_type in i]) + 1
     f = open("Pictures1/" + image_type + "_"+ str(total), 'wb')
     f.write(raw_img)
     f.close()
driver = webdriver.Firefox()
driver.get("https://images.google.com/")
elem = driver.find_element_by_xpath('/html/body/div/div[3]/div[3]/form/div[2]/div[2]/div[1]/div[1]/div[3]/div/div/div[2]/div/input[1]')
elem.clear()
elem.send_keys("parrot")
elem.send_keys(Keys.RETURN)
image_type = "parrot_defG"
images=[]
total=0
time.sleep(10)
for a in driver.find_element_by_xpath('//div[@class="rg_meta"]/text()'):
     link =json.loads(a)["ou"]
     thread = Thread(target = threaded_func, args = (link,total))
     thread.start()
     thread.join()
     total+=1

打印链接会导致：

http://media.web.britannica.com/eb-media/89/89689-004-4C85E0F0.jpg