我正在尝试用随机整数创建一个数组，然后反转数组答案

【问题标题】：I'm trying to create an array with random integers, then reverse the array我正在尝试用随机整数创建一个数组，然后反转数组
【发布时间】：2020-11-10 08:16:06
【问题描述】：

这是完整的问题：创建一个数组来存储 1 到 40 之间的 5 个随机整数。打印给定数组中所有元素的总和和平均值。最后，向后打印数组！

这是我目前所拥有的：

import random
print("12 random numbers between 5 and 50")
randNumbers = random.randint(5, 50)
num1=randNumbers(1)
print(num1)
randNumbers.reverse()
for element in randNumbers:
  print(element)
sum=sum+nums
avg=(round(sum/n,3))
if (nums%2==0):
  even+=1
else:
  odd+=1
print("\nSum: ",sum)
print("Average: ",round(avg,1))

我是编码新手，我不确定如何解决它。如有任何帮助，我将不胜感激！

【问题讨论】：

您不知道如何解决？怎么了？
SO 不是完成作业的平台

标签： python arrays random reverse

【解决方案1】：

根据您的书面提示，这里有一个解决方案：

import random

# five rand int between 1 and 40
randNumbers = [random.randint(1, 40) for _ in range(5)]
print(randNumbers)

# print sum stored in randNumbers
print(sum(randNumbers))

# print avg stored in randNumbers
print(sum(randNumbers)/len(randNumbers))

# print array backwards
print(randNumbers[::-1])

【讨论】：

【解决方案2】：

这是文本中问题的答案，但它与您的代码不匹配，所以希望这就是您想要的。

import random

print("12 random numbers between 5 and 50")
randNumbers = []
for i in range(0, 12):
    randNumbers.append(random.randint(1, 40))

print("Original: " + str(randNumbers))
print("Sum: " + str(sum(randNumbers)))
print("Average: " + str(sum(randNumbers) / len(randNumbers)))

randNumbers.reverse()
print("Reversed: " + str(randNumbers))

【讨论】：

【解决方案3】：

详细的回答

import random

print("12 random numbers between 5 and 50")
randNumbers = [] # initialize an empty array
for i in range(5): # create 5 times..
    randNum = random.randint(1, 40) # ..a random number between 1 and 40
    randNumbers.append(randNum) # then add it to the array
print(f"array is {randNumbers}")

# Print sum of the elements of array
s = 0 # initialize the sum s to 0
for element in randNumbers:
    s = s + element # add each element of the array to the sum s
print(f"sum is {s}")

# Print the average
size = len(randNumbers) # the size of the array
average = s / size # the average of the array
print(f"average is {average}")

# Print the array backwards
backed = []
for i in range(1, size+1):
    backed.append(randNumbers[-i])
print(f"backward array is{backed}")

简答：

import random

randNumbers = [random.randint(1, 40) for i in range(5)]
print(f"array is {randNumbers}")

s = sum(randNumbers)
print(f"sum is {s}")

avg = s / len(randNumbers)
print(f"average is {avg}")

backed = list(reversed(randNumbers))
print(f"backward array is{backed}")

【讨论】：

我不断收到“TypeError: 'int' object is not callable”
是的，这就是您在第 4 行得到的结果，因为上一行的 random.randint(.., ..) 返回一个整数而不是数组。你也可以使用括号 [ ] 而不是括号 ( ) 来访问数组中的元素，如果那是一个数组的话。

【解决方案4】：

我强烈建议您将 numpy 库用于所有这些数学运算。

代码：

import numpy as np
rand_nums = np.random.randint(1,40,5)
print(f"Random integer array: {rand_nums}")
print(f"Sum: {rand_nums.sum()}")
print(f"Average: {rand_nums.mean()}")
print(f"Backwards array: {rand_nums[::-1]}")

【讨论】：