如何通过编号拆分字符串？

Question

我希望将以下语料库拆分为多个部分：

corpus = '1  Write short notes on the anatomy of the Circle of Willis including normal variants.     2  Write short notes on the anatomy of the radiological spaces of the orbit excluding the eyeball.      3  Write short notes on the anatomy of the axis (C2 vertebra).      4  Write short notes on the anatomy of the corpus callosum.      5  Write short notes on the anatomy of the posterior division of the internal iliac artery  6  Write short notes on the anal canal including sphincters.               
      '

如下：

['Write short notes on the anatomy of the Circle of Willis including normal variants.', 'Write short notes on the anatomy of the radiological spaces of the orbit excluding the eyeball.', 'Write short notes on the anatomy of the axis (C2 vertebra).', 'Write short notes on the anatomy of the posterior division of the internal iliac artery', 'Write short notes on the anal canal including sphincters.']

我写了这个，但不起作用：

for i in [int(s) for s in corpus.split() if s.isdigit()]:
    answer = corpus.split(str(i))

print(answer)

我能做什么？

Answer 1

对于您的示例数据，您还可以匹配零次或多次空格，后跟一位或多位数字和 2 次空格以匹配 split on：

*\d+

print (filter(None, re.split(' *\d+  ', corpus)))

Demo

为了清楚起见，您可以将空格放在字符类中，后跟量词 [ ]*\d+[ ]{2}。

Answer 2

您标记了regex，但提供了非正则表达式解决方案。这是您的 OP 的非正则表达式正确解决方案。

分割空格是可以的，然后将文本部分累积到一个临时变量中，直到遇到下一个数字，然后将临时添加到您的整体结果中。

由于不可变性，使用列表存储临时（部分）比附加到字符串更有效。

跳过存储数字本身：

corpus = '1  Write short notes on the anatomy of the Circle of Willis including normal variants.     2  Write short notes on the anatomy of the radiological spaces of the orbit excluding the eyeball.      3  Write short notes on the anatomy of the axis (C2 vertebra).      4  Write short notes on the anatomy of the corpus callosum.      5  Write short notes on the anatomy of the posterior division of the internal iliac artery  6  Write short notes on the anal canal including sphincters.'               

allparts = []  # total result
part = []      # parts that belong to one number
for p in corpus.split():
    if p.isdigit():      # if a number
        if part:             # if stored something
            allparts.append(' '.join(part))   # add it to result
            part=[]
        continue         # skip storing the number  

    part.append(p)      # add to part

if part:   # add rest
    allparts.append(' '.join(part))

print(allparts)

输出：

['Write short notes on the anatomy of the Circle of Willis including normal variants.', 
 'Write short notes on the anatomy of the radiological spaces of the orbit excluding the eyeball.', 
 'Write short notes on the anatomy of the axis (C2 vertebra).', 
 'Write short notes on the anatomy of the corpus callosum.', 
 'Write short notes on the anatomy of the posterior division of the internal iliac artery', 
 'Write short notes on the anal canal including sphincters.']

Answer 3

使用re.split 和列表推导，使用str.strip 删除最终的空格：

import re
result = [
    phrase for phrase in map(str.strip, re.split('\d+\s\s', corpus)) if phrase
]

结果：

['Write short notes on the anatomy of the Circle of Willis including normal variants.',
 'Write short notes on the anatomy of the radiological spaces of the orbit excluding the eyeball.',
 'Write short notes on the anatomy of the axis (C2 vertebra).',
 'Write short notes on the anatomy of the corpus callosum.',
 'Write short notes on the anatomy of the posterior division of the internal iliac artery',
 'Write short notes on the anal canal including sphincters.']

Answer 4

尝试使用 re.split() 和正则表达式 + strip()

a = "1  hello.  2  my name is. 3  maat."

answer = [s.strip(" ") for s in filter(None, re.split(" *\d+ ", a))]

print(answer) #['hello.', 'my name is.', 'maat.']

re.split() 几乎是 split() 但它也包含分隔符 / strip(" ") 从 s 中删除空格