删除列表列表中“”中的空格

Question

results = [[['2020 is the year', '29 year old "Samuel G"', '25 year old "John P Krul"', '40 year old "Trey Nunez S"', '22 year old "Fiona S Paul"', '50 year old "Sean J Beal"']]]

我尝试了以下，但这似乎摆脱了python3中“”中的中间词。

print([re.sub(r'"(\w+)(\s(\w+))*"', '"\\1\\3"', x.lower()) for x in results[0]])

我想要的输出是

results = [[['2020 is the year', '29 year old "samuelg"', '25 year old "johnpkrul"', '40 year old "treynunezs"', '22 year old "fionaspaul"', '50 year old "seanjbeal"']]]

仅删除“”中的“”和小写字母之间的“”，以便“John P Krul”到“johnpkrul”，同时保持所有内容相同。

代码需要改什么？

Answer 1

你可以试试这个。

def f(x): #Takes re.match object as input
    a=x.group() #extractting the match
    return a.replace(' ','').lower() #them to lower and removing spaces

[re.sub(r'\"([^"]*)\"',f,i) for i in results]

---

['2020 is the year',
 '29 year old "samuelg"',
 '25 year old "johnpkrul"',
 '40 year old "treynunezs"',
 '22 year old "fionaspaul"',
 '50 year old "seanjbeal"']

编辑： 对于列表列表的列表

[[[re.sub(r'\"([^"]*)\"',f,i) for i in lst2] for lst2 in lst1] for lst1 in results]

输出：

[[['2020 is the year',
   '29 year old "samuelg"',
   '25 year old "johnpkrul"',
   '40 year old "treynunezs"',
   '22 year old "fionaspaul"',
   '50 year old "seanjbeal"']]]