将字符串拆分为字母和数字，保留符号

Question

鉴于下面的代码，来自this question 的接受答案：

import re    
pathD = "M30,50.1c0,0,25,100,42,75s10.3-63.2,36.1-44.5s33.5,48.9,33.5,48.9l24.5-26.3"    
print(re.findall(r'[A-Za-z]|-?\d+\.\d+|\d+',pathD))    
['M', '30', '50.1', 'c', '0', '0', '25', '100', '42', '75', 's', '10.3', '-63.2', '36.1', '-44.5', 's', '33.5', '48.9', '33.5', '48.9', 'l', '24.5', '-26.3']

如果我在 pathD 变量中包含诸如“$”或“£”之类的符号，re 表达式将跳过它们，因为它以 [A-Za-z] 和数字为目标

[A-Za-z] # words
|
-?\d+\.\d+ # floating point numbers
|
\d+ # integers

我如何修改上面的正则表达式模式以同时保留非字母数字符号，根据下面的所需输出？

new_pathD = '$100.0thousand'

new_re_expression = ???

print(re.findall(new_re_expression, new_pathD))

['$', '100.0', 'thousand']

~~~

下面的相关 SO 帖子，尽管我无法完全找到如何在拆分练习中保留符号：

Split string into letters and numbers

split character data into numbers and letters

Python regular expression split string into numbers and text/symbols

Python - Splitting numbers and letters into sub-strings with regular expression

Answer 1

试试这个：

compiled = re.compile(r'[A-Za-z]+|-?\d+\.\d+|\d+|\W')
compiled.findall("$100.0thousand")
# ['$', '100.0', 'thousand']

这是一个高级版™

advanced_edition = re.compile(r'[A-Za-z]+|-?\d+(?:\.\d+)?|(?:[^\w-]+|-(?!\d))+')

区别在于：

compiled.findall("$$$-100thousand")  # ['$', '$', '$', '-', '100', 'thousand']
advanced_edition.findall("$$$-100thousand")  # ['$$$', '-100', 'thousand']