如何从行之间删除换行符而不从行尾删除换行符python？

Question

我的输入是一个大的 csv 文件，其中的行如下：

"7807371008","Sat Jan 16 00:07:46 +0000 2010","@bigg_robb welcome to the party life of politics","T 33.417474,-86.705343","al","23845121","1381","502","Wed Mar 11 22:38:27 +0000 2009","2468"

我想要的输出是一个新文件，其中第一列和第三列仅删除了所有特殊字符：

7807371008,  bigg robb welcome to the party life of politics

但是在文本之间有一些换行符的行，即使它在技术上不是该行的末尾。在这种情况下，我收到错误：

IndexError: list index out of range

这样的行的一个例子是：

"7807376607","Sat Jan 16 00:07:57 +0000 2010","RT @CBS8News:The commander of Gov. Riley's task
force on illegal gambling resigns after winning $2,300 at a MS casino.
gt;#conflictofinterest","Montgomery, Alabama","al","33358058","84","164","Mon Apr 20 00:48:37 +0000 2009","4509"

我的代码是：

import csv
import sys
import re

with open('al.csv') as f:
    for line in f:

        j = next(csv.reader([line]))
        id1 = j[0]
        id2 = re.sub('[^A-Za-z0-9\.]+',' ',id1)
        tt1 = j[2]
        tt2 = re.sub('[^A-Za-z0-9\.]+',' ',tt1)
        print id2.strip()+", "+tt2.lower()

我该如何解决这个问题？请帮忙。

Answer 1

您应该将逗号 , 指定为您的 csv 文件分隔符（或基于您的文件的正确分隔符）而且 csv 阅读器对象没有您循环的行，您需要通过循环访问行来访问 @ 987654322@对象（spamreader）：

>>> import csv
>>> with open('al.csv', 'rb') as csvfile:
...     spamreader = csv.reader(csvfile, delimiter=',')
...     for row in spamreader:
            print re.sub('[^A-Za-z0-9\.]+',' ',row[2]) + row[0]