【发布时间】:2015-01-13 17:40:48
【问题描述】:
作为这个问题的延伸Split Python Flask app into multiple files
我想使用 Flask-Menu 并将每个单独的菜单页面放在它自己的 Python 文件中。
这是我的主站点 main.py 文件,其中包含 /first 菜单项
from flask import Flask, render_template, Blueprint, abort
from flask_wtf import Form
from flask.ext import menu
from wtforms import HiddenField
from second import bp_second
class EmptyForm(Form):
hidden_field = HiddenField('You cannot see this', description='Nope')
def create_app(configfile=None):
app = Flask(__name__)
app.register_blueprint(bp_second)
menu.Menu(app=app)
@app.route('/')
@menu.register_menu(app, '.', 'Home')
def index():
form = EmptyForm()
form.validate_on_submit()
return render_template('index.html', form=form)
@app.route('/first')
@menu.register_menu(app, '.first', 'First', order=0)
def first():
form = EmptyForm()
form.validate_on_submit()
return render_template('index.html', form=form)
return app
if __name__ == '__main__':
create_app().run(debug=True)
我有一个名为 second.py 的菜单项,这里有 /second 菜单项
from flask import Blueprint, render_template
from flask_wtf import Form
from flask.ext import menu
from wtforms import TextField
class TextForm(Form):
text = TextField(u'text', [validators.Length(min=2, max=5, message="my item")])
bp_second = Blueprint('second', __name__, url_prefix='/second')
@bp_second.route("/second")
@menu.register_menu(bp_second, '.second', 'Second', order=1)
def second():
form = TickerForm()
form.validate_on_submit() #to get error messages to the browser
return render_template('index.html', form=form)
当我单击/second 的菜单项时,我收到了"GET /meta HTTP/1.1" 404 - 消息。 / 和 /first 菜单项工作
【问题讨论】: