【发布时间】:2016-02-21 01:48:41
【问题描述】:
我正在尝试为我的程序创建登录脚本。我能够编写一个基本脚本来测试我的登录框架,但现在我基本上登录后能够访问另一个框架。
这是我的脚本的一部分:
#!/usr/bin/python
from tkinter import *
from tkinter import ttk
import tkinter as tk
import tkinter.messagebox as tm
Large_Font = ("Verdana", 18)
Small_Font = ("Verdana", 12)
class ATM(tk.Tk):
def __init__(self, *args, **kwargs):
tk.Tk.__init__(self, *args, **kwargs)
tk.Tk.wm_title(self, "ATM Simulator")
container = tk.Frame(self)
container.pack(side = "top", fill ="both", expand =True)
container.grid_rowconfigure(100, weight=1)
container.grid_columnconfigure(100, weight=1)
#Create Frame Library and use For Loop to switch between frames
self.frames = {}
for i in (LogIn, WelcomePage, Checking, Savings, Transfer):
frame = i(container, self)
self.frames[i] = frame
frame.grid(row= 100, column = 100, sticky= "nsew")
self.show_frame(LogIn)
def show_frame(self, cont):
frame = self.frames[cont]
frame.tkraise()
class LogIn(tk.Frame):
def __init__(self, parent, controller):
tk.Frame.__init__(self, parent)
global act_num_entry
global pin_num_entry
label = Label(self, text = "Login Using Account and PIN Numbers", font=Small_Font)
label.pack(pady=50, padx=50)
act_num_label = Label(self, text="Account Number")
act_num_entry = Entry(self)
pin_num_label = Label(self, text="PIN Number")
pin_num_entry = Entry(self, show="*")
act_num_label.pack(pady=5, padx=5)
pin_num_label.pack(pady=5, padx=5)
act_num_entry.pack(pady=5, padx=5)
pin_num_entry.pack(pady=5, padx=5)
logBTN = ttk.Button(self, text="Enter",
command =self.log_check)
logBTN.pack()
quitButton = ttk.Button(self, text = "End Transaction", command = quit)
quitButton.pack()
def log_check(self):
#default test pin and account numbers
act_num=1234567
pin_num=1234
#This Try/Except handles the non-integer values being entered
try:
actNum = int(act_num_entry.get())
pinNum = int(pin_num_entry.get())
except:
tm.showerror("Login Error", "Invalid Entry")
pass
if actNum == act_num and pinNum == pin_num:
#Message Window only used to to prove my log_check function works
tm.showinfo("ATM Login", "Login Successful")
'''Insert script to open the WelcomePage(tk.Frame) method'''
elif actNum != act_num:
tm.showerror("Login Error", "Invalid Account Number")
elif pinNum != pin_num:
tm.showerror("Login Error", "Invalid PIN Number")
else:
tm.showerror("Login Error", "Invalid Entry")
class WelcomePage(tk.Frame):
#Welcome Page Window
def __init__(self, parent, controller):
tk.Frame.__init__(self, parent)
label = Label(self, text = "Welcome to the ATM Simulator", font = Large_Font)
label.pack(pady=100, padx=100)
checkButton = ttk.Button(self, text = "Checking Account",
command = lambda: controller.show_frame(Checking))
checkButton.pack()
saveButton = ttk.Button(self, text = "Savings Account",
command = lambda: controller.show_frame(Savings))
saveButton.pack()
transButton = ttk.Button(self, text = "Transfer Funds",
command = lambda: controller.show_frame(Transfer))
transButton.pack()
quitButton = ttk.Button(self, text = "End Transaction", command = self.client_exit)
quitButton.pack()
def client_exit(self):
exit()
所以我想从我的内部调用我的WelcomePage(tk.Frame) 方法
if actNum == act_num and pinNum == pin_num: 函数,所以我基本上可以登录到我的程序。我尝试使用我的 show_frame 函数访问WelcomePage(tk.Frame),但我无法访问,因为我知道该函数是ATM(tk.Tk) 类而不是LogIn(tk.Frame) 的一部分。这是否可以完成我想要的方式,或者我将不得不编写另一个登录脚本来完成这个?
【问题讨论】:
-
小心术语:
WelcomePage(tk.Frame)不是一种方法。WelcomePage是一个类。您不“调用”类,而是“实例化”它们(即:创建它们的实例)。
标签: python user-interface python-3.x tkinter