从按钮调用 Pyserial 函数时 Tkinter 冻结

Question

我正在为我的串行通信程序创建一个图形界面。 gui 的布局是按照我的意愿设置的，我已经开始尝试添加一些串行代码。但是，我遇到了一个问题。当我单击“测试连接”按钮或 b1 时，程序冻结并停止响应。不是下面的代码遗漏了我认为不必要的东西。 我已将问题缩小到 read = ser.read(1)。出于某种原因 ser.read() 正在杀死它。 提前感谢您的帮助！

class COMS_app(Tkinter.Tk):
    def __init__(self,parent):
        Tkinter.Tk.__init__(self,parent)
        self.parent = parent
        self.platform_check()
        self.initialize()

    def initialize(self):
        self.grid()

        self.scrollbar = Tkinter.Scrollbar(self, orient = 'vertical', bd = 5)
        self.scrollbar.grid(column = 2, row = 0, rowspan = 2, sticky = 'NSE')

        self.com = Tkinter.Text(self, fg = "blue", height = 20, borderwidth = 5, padx = 5, pady = 5, relief = 'ridge')
        self.com.grid(column = 0, row =0, columnspan = 2)

        self.com.insert('1.0', 'COMS Terminal:')

        self.scrollbar.config(command = self.com.yview)

        self.inf = Tkinter.Text(self, fg = "blue", height = 8, borderwidth = 5, padx = 5, pady = 5, relief = 'ridge')
        self.inf.grid(column = 0, row =7, columnspan = 2)

        self.tb2Variable = Tkinter.StringVar()
        self.tb2 = Tkinter.Entry(self,textvariable = self.tb2Variable)
        self.tb2.grid(column=1,row=2, sticky='W')
        self.tb2.bind("<Return>", self.OnPressEnter)
        self.tb2Variable.set(u"Enter File Name")


        b1 = Tkinter.Button(self, text = u"Test Connection", borderwidth = 5, relief = 'ridge', command = self.OnButtonClick1)
        b1.grid(column = 0, row = 1, sticky = 'W')

        b2 = Tkinter.Button(self, text = u"Receive File", borderwidth = 5, relief = 'ridge', command = self.OnButtonClick2)
        b2.grid(column = 0, row = 2, sticky = 'W')

        b3 = Tkinter.Button(self, text = u"Send AT C/D", borderwidth = 5, relief = 'ridge', command = self.OnButtonClick3)
        b3.grid(column = 0, row =3, sticky = 'W')

        b4 = Tkinter.Button(self, text = u"Send Text", borderwidth = 5, relief = 'ridge', command = self.OnButtonClick4)
        b4.grid(column = 0, row = 4, sticky = 'W')

        b5 = Tkinter.Button(self, text = u"End Program", borderwidth = 5, relief = 'ridge', command = self.OnButtonClick5)
        b5.grid(column = 0, row = 5, sticky = 'W')

        b6 = Tkinter.Button(self, text = u"Get Help", borderwidth = 5, relief = 'ridge', command = self.OnButtonClick6)
        b6.grid(column = 0, row = 6, sticky = 'W')

        self.resizable(False, False)

    def OnButtonClick1(self):
        self.test_con()


    def OnButtonClick2(self):
        pass

    def OnButtonClick3(self):
        pass

    def OnButtonClick4(self):
        pass

    def OnButtonClick5(self):
        pass

    def OnButtonClick6(self):
        pass

    def OnPressEnter(self,event):
        pass


    def test_con(self):
        read = ser.read(1)
        tran = 'OUTWAY'
        rec = 'INWAY'
        ser.write(tran)
        self.inf.insert(Tkinter.INSERT, '\n<<' + tran)
        while not read:
            pass
        if read == rec:
            self.inf.insert(Tkinter.INSERT, '\n<<' +rec)
        elif read == FALSE:
            self.inf.insert(Tkinter.INSERT, '\n- - NO RESPONSE FROM SERVER')
        else:
            self.inf.insert(Tkinter.INSERT, '\n- - INVALID RESPONSE FROM SERVER: SERVER:<<' + read)



    if __name__ == "__main__":
        app = COMS_app(None)
        app.title('INS Communications Beta 2.0')
        app.mainloop()

Answer 1

我对 pyserial 一无所知，但听起来ser.read(1) 正在阻塞，直到它返回一个字节。如果这是一个阻塞调用，那将冻结你的 GUI。您必须将串行端口配置为允许非阻塞调用，或者在单独的线程中进行读取。