在Angular 6中按对象字段对对象数组进行排序[重复]

Question

我从一个从 json 端点获取数据的解析器获取了一组“产品”。

ngOnInit() {
  this.products = this._route.snapshot.data.products;
  console.log('products: ', this.products);
}

这个数组中的一个对象的格式是什么

 {
    "id": 3645,
    "date": "2018-07-05T13:13:37",
    "date_gmt": "2018-07-05T13:13:37",
    "guid": {
        "rendered": ""
    },
    "modified": "2018-07-05T13:13:37",
    "modified_gmt": "2018-07-05T13:13:37",
    "slug": "vpwin",
    "status": "publish",
    "type": "matrix",
    "link": "",
    "title": {
        "rendered": "VPWIN"
    },
    "content": {
        "rendered": "",
        "protected": false
    },
    "featured_media": 0,
    "parent": 0,
    "template": "",
    "better_featured_image": null,
    "acf": {
        "domain": "SMB",
        "ds_rating": "3",
        "dt_rating": ""
    },
    ...
},

我想做的是按字段title.rendered对这个数组进行排序

在过去，在 AngularJS 中，我会简单地在设置为该字段的模板中使用 orderBy 管道。显然，这在 Angular 中已被删除，并且从研究来看，似乎首选的方法是对数据本身进行排序，例如在 ngOnInit 中。

但我不知道如何按producs.title.rendered 对products 进行排序。

Answer 1

您可以简单地使用Arrays.sort()

array.sort((a,b) => a.title.rendered.localeCompare(b.title.rendered));

工作示例：

var array = [{"id":3645,"date":"2018-07-05T13:13:37","date_gmt":"2018-07-05T13:13:37","guid":{"rendered":""},"modified":"2018-07-05T13:13:37","modified_gmt":"2018-07-05T13:13:37","slug":"vpwin","status":"publish","type":"matrix","link":"","title":{"rendered":"VPWIN"},"content":{"rendered":"","protected":false},"featured_media":0,"parent":0,"template":"","better_featured_image":null,"acf":{"domain":"SMB","ds_rating":"3","dt_rating":""},},{"id":3645,"date":"2018-07-05T13:13:37","date_gmt":"2018-07-05T13:13:37","guid":{"rendered":""},"modified":"2018-07-05T13:13:37","modified_gmt":"2018-07-05T13:13:37","slug":"vpwin","status":"publish","type":"matrix","link":"","title":{"rendered":"adfPWIN"},"content":{"rendered":"","protected":false},"featured_media":0,"parent":0,"template":"","better_featured_image":null,"acf":{"domain":"SMB","ds_rating":"3","dt_rating":""}},{"id":3645,"date":"2018-07-05T13:13:37","date_gmt":"2018-07-05T13:13:37","guid":{"rendered":""},"modified":"2018-07-05T13:13:37","modified_gmt":"2018-07-05T13:13:37","slug":"vpwin","status":"publish","type":"matrix","link":"","title":{"rendered":"bbfPWIN"},"content":{"rendered":"","protected":false},"featured_media":0,"parent":0,"template":"","better_featured_image":null,"acf":{"domain":"SMB","ds_rating":"3","dt_rating":""}}];
array.sort((a,b) => a.title.rendered.localeCompare(b.title.rendered));
 
 console.log(array);

Answer 2

试试这个

products.sort(function (a, b) {
  return a.title.rendered - b.title.rendered;
});

或

您可以导入 lodash/underscore 库，它有许多构建函数可用于操作、过滤、排序数组等等。

使用下划线：（以下仅为示例）

import * as _ from 'underscore';
let sortedArray = _.sortBy(array, 'title'); 

Answer 3

未经测试，但应该可以工作

 products.sort((a,b)=>a.title.rendered > b.title.rendered)