有谁知道为什么我没有得到输出，代码编译但没有返回输出

Question

employees =[
    {
        "name": "John Doe",
        "job": "Software Engineer",
        "City": "Vancouver",
        "age": 34,
        "status": "single"
    },
    {
        "name": "Alicia Smith",
        "job": "Director",
        "City": "New York",
        "age": 38,
        "status": "Married"
    }
] 

keys = ["name", "age"]


if "name" and "age" in employees:
 newDict = employees.pop("name" and "age")
 print(newDict)

Answer 1

您可以在list comprehension 中使用dict comprehension 来实现单行。

print([{k: v for k, v in d.items() if k not in keys} for d in employees])

如果您想在多行中执行它，您应该在从中删除项目之前制作字典的副本。否则会出现以下错误。

RuntimeError: dictionary changed size during iteration

Answer 2

您的代码中有一些错误。我相信您正在尝试从字典中删除键 name 和 age。请尝试以下操作：

employees = [
    {
        "name": "John Doe",
        "job": "Software Engineer",
        "City": "Vancouver",
        "age": 34,
        "status": "single"
    },
    {
        "name": "Alicia Smith",
        "job": "Director",
        "City": "New York",
        "age": 38,
        "status": "Married"
    }
]

newDict = []
for d in employees:   # First iterate over the dictionaries
    if "name" in d:   # If the key "name" is there in the dictionary
        d.pop("name") # Remove it
    if "age" in d:    # Check if "age" is there in the keys
        d.pop("age")  # Remove it too if present
    newDict.append(d) # Add the updated dictionary to our list
print(newDict)

Answer 3

首先你在代码中有两个错误，第一个是因为 if 语句不正确，这就是为什么没有被执行。其次，你不能在数组中弹出一个字典，你必须选择每个数组，然后像这个解决方案一样弹出它们或将它们放入循环中

employees =[ { "name": "John Doe", "job": "Software Engineer", "City": "Vancouver", "age": 34, "status": "single" }, { "name": "Alicia Smith", "job": "Director", "City": "New York", "age": 38, "status": "Married" } ]
newDict = []
for i in employees:
    if "name" and "age" in i:
        i.pop("name" and "age")
        newDict.append(i)
print(newDict)