【发布时间】:2016-04-26 18:59:21
【问题描述】:
我有以下代码:
import json
src_vol1 = {'provider_id':'src1'}
src_vol2 = {'provider_id':'src2'}
get_snapshot_params = lambda src_volume, trg_volume: {
'volumeId': src_volume['provider_id'],
'snapshotName': trg_volume['id']}
trg_vol1 = {'id':'trg1'}
trg_vol2 = {'id':'trg2'}
src_vols = [src_vol1, src_vol2]
trg_vols = [trg_vol1, trg_vol2]
snapshotDefs = map(get_snapshot_params , src_vols, trg_vols)
params = {'snapshotDefs': snapshotDefs}
json.dumps(params)
我需要它在 Python3 和 Python2.7 上都能工作,但在 Python3 上我得到了
Traceback (most recent call last):
File "./prog.py", line 16, in <module>
File "/usr/lib/python3.4/json/__init__.py", line 230, in dumps
return _default_encoder.encode(obj)
File "/usr/lib/python3.4/json/encoder.py", line 192, in encode
chunks = self.iterencode(o, _one_shot=True)
File "/usr/lib/python3.4/json/encoder.py", line 250, in iterencode
return _iterencode(o, 0)
File "/usr/lib/python3.4/json/encoder.py", line 173, in default
raise TypeError(repr(o) + " is not JSON serializable")
TypeError: <map object at 0xb72a1a0c> is not JSON serializable
我试图将 dict() 放在参数周围,但没有用。 有什么区别?我在文档中没有找到任何东西。
【问题讨论】:
标签: python json python-2.7 python-3.x pickle