按 8 位日期字符串对多个列表进行排序

Question

我有 4 个需要按日期排序的列表。一个列表包含文件日期，其他关于文件名的信息如何不带扩展名、大小和最后一个带扩展名。现在我想对排序后的列表和与条目编号匹配的其他列表进行排序。我尝试使用 Zip the Listst 然后排序，但这根本不起作用。

Datestring 列表具有日期条目，例如：

20200329 20200719 20200804 20200919

这是我的代码，它是如何不工作的。我错过了什么吗？

# ls = []   # loaded filelist
# fs = []   # filename list
# ps = []   # filetype list
# ts = []   # fliedate list

f = open(sys.argv[4], "w")
AB = zip(ts,fs,ps,fz)
AB.sort()
ts[:] = [t[0] for t in AB]
fs[:] = [t[1] for t in AB]
ps[:] = [t[2] for t in AB]
fz[:] = [t[3] for t in AB]

Answer 1

我会假设您的日期字符串是正确的日期时间对象，尽管这仍然适用于字符串 ["20200329", "20200719", "20200804", "20200919"]:

ts, fs, ps, fz = zip(*sorted(zip(ts, fs, ps, fz)))

演示：

In [4]: ts = ["20200719", "20200804", "20200919", "20200329"]
   ...: fs = ["fs719", "fs804", "fs919", "fs329"]
   ...: ps = ["ps719", "ps804", "ps919", "ps329"]
   ...: fz = ["fz719", "fz804", "fz919", "fz329"]

In [5]: ts, fs, ps, fz = zip(*sorted(zip(ts, fs, ps, fz)))

In [6]: ts
Out[6]: ('20200329', '20200719', '20200804', '20200919')

In [7]: fs
Out[7]: ('fs329', 'fs719', 'fs804', 'fs919')

In [8]: ps
Out[8]: ('ps329', 'ps719', 'ps804', 'ps919')

In [9]: fz
Out[9]: ('fz329', 'fz719', 'fz804', 'fz919')