【发布时间】:2015-07-30 22:19:21
【问题描述】:
我有一个 JSON,我想将 JSON 的值作为 PHP 变量。如果我回显变量$jne,结果将是这样的。
{
"rajaongkir":{
"query":{
"origin":"501",
"destination":"114",
"weight":1700,
"courier":"jne"
},
"status":{
"code":200,
"description":"OK"
},
"origin_details":{
"city_id":"501",
"province_id":"5",
"province":"DI Yogyakarta",
"type":"Kota",
"city_name":"Yogyakarta",
"postal_code":"55000"
},
"destination_details":{
"city_id":"114",
"province_id":"1",
"province":"Bali",
"type":"Kota",
"city_name":"Denpasar",
"postal_code":"80000"
},
"results":[
{
"code":"jne",
"name":"Jalur Nugraha Ekakurir (JNE)",
"costs":[
{
"service":"OKE",
"description":"Ongkos Kirim Ekonomis",
"cost":[
{
"value":38000,
"etd":"4-5",
"note":""
}
]
},
{
"service":"REG",
"description":"Layanan Reguler",
"cost":[
{
"value":44000,
"etd":"2-3",
"note":""
}
]
},
{
"service":"SPS",
"description":"Super Speed",
"cost":[
{
"value":349000,
"etd":"",
"note":""
}
]
},
{
"service":"YES",
"description":"Yakin Esok Sampai",
"cost":[
{
"value":98000,
"etd":"1-1",
"note":""
}
]
}
]
}
]
}
}
这就是我尝试获取价值的方式,我想在“成本”中获取“价值”
$content = $jne;
$json = json_decode($content, true);
$value = $json[results][0][costs][1][cost][0][value];
感谢您的帮助..
【问题讨论】:
-
为数组索引添加引号(例如:$json['results'])
-
你要使用哪个json值
-
@Sunil Pachlangia “成本”中的“价值”
-
顺便说一句,有 4 种不同的“成本”,每种都有“价值”。