scipy.ndimage.rotate 接受 reshape= 参数:
重塑 : 布尔型,可选
如果reshape 为真,则调整输出形状,以便输入
数组完全包含在输出中。默认为真。
所以要“剪裁”边缘,您只需调用 scipy.ndimage.rotate(img, ..., reshape=False)。
from scipy.ndimage import rotate
from scipy.misc import face
from matplotlib import pyplot as plt
img = face()
rot = rotate(img, 30, reshape=False)
fig, ax = plt.subplots(1, 2)
ax[0].imshow(img)
ax[1].imshow(rot)
scipy.ndimage.zoom 的情况更复杂。
一个简单的方法是 zoom 整个输入数组,然后使用切片索引和/或零填充使输出与输入大小相同。但是,在您增加图像大小的情况下,插入无论如何只会在边缘被剪掉的像素是很浪费的。
相反,您可以在应用 zoom 之前仅索引输入中将落在输出数组范围内的部分:
import numpy as np
from scipy.ndimage import zoom
def clipped_zoom(img, zoom_factor, **kwargs):
h, w = img.shape[:2]
# For multichannel images we don't want to apply the zoom factor to the RGB
# dimension, so instead we create a tuple of zoom factors, one per array
# dimension, with 1's for any trailing dimensions after the width and height.
zoom_tuple = (zoom_factor,) * 2 + (1,) * (img.ndim - 2)
# Zooming out
if zoom_factor < 1:
# Bounding box of the zoomed-out image within the output array
zh = int(np.round(h * zoom_factor))
zw = int(np.round(w * zoom_factor))
top = (h - zh) // 2
left = (w - zw) // 2
# Zero-padding
out = np.zeros_like(img)
out[top:top+zh, left:left+zw] = zoom(img, zoom_tuple, **kwargs)
# Zooming in
elif zoom_factor > 1:
# Bounding box of the zoomed-in region within the input array
zh = int(np.round(h / zoom_factor))
zw = int(np.round(w / zoom_factor))
top = (h - zh) // 2
left = (w - zw) // 2
out = zoom(img[top:top+zh, left:left+zw], zoom_tuple, **kwargs)
# `out` might still be slightly larger than `img` due to rounding, so
# trim off any extra pixels at the edges
trim_top = ((out.shape[0] - h) // 2)
trim_left = ((out.shape[1] - w) // 2)
out = out[trim_top:trim_top+h, trim_left:trim_left+w]
# If zoom_factor == 1, just return the input array
else:
out = img
return out
例如:
zm1 = clipped_zoom(img, 0.5)
zm2 = clipped_zoom(img, 1.5)
fig, ax = plt.subplots(1, 3)
ax[0].imshow(img)
ax[1].imshow(zm1)
ax[2].imshow(zm2)