您可以使用 itertools 获取切片,使用 itemgetter 获取列:
import numpy as np
from operator import itemgetter
import csv
with open(filename) as f:
from itertools import islice,imap
r = csv.reader(f)
np.genfromtxt(imap(itemgetter(1),islice(r, start, end+1)))
对于python3,你可以使用fromiter,上面的代码你需要指定dtype:
import numpy as np
from operator import itemgetter
import csv
with open("sample.txt") as f:
from itertools import islice
r = csv.reader(f)
print(np.fromiter(map(itemgetter(0), islice(r, start, end+1)), dtype=float))
与其他答案一样,您也可以将 islice 对象直接传递给 genfromtxt 但对于 python3,您需要以二进制模式打开文件:
with open("sample.txt", "rb") as f:
from itertools import islice
print(np.genfromtxt(islice(f, start, end+1), delimiter=",", usecols=cols))
有趣的是,对于使用 itertools.chain 的多个列,如果所有 dtype 都相同,那么整形的效率会提高一倍以上:
from itertools import islice,chain
with open("sample.txt") as f:
r = csv.reader(f)
arr =np.fromiter(chain.from_iterable(map(itemgetter(0, 4, 10),
islice(r, 4, 10))), dtype=float).reshape(6, -1)
在你的示例文件上:
In [27]: %%timeit
with open("sample.txt", "rb") as f:
(np.genfromtxt(islice(f, 4, 10), delimiter=",", usecols=(0, 4, 10),dtype=float))
....:
10000 loops, best of 3: 179 µs per loop
In [28]: %%timeit
with open("sample.txt") as f:
r = csv.reader(f) (np.fromiter(chain.from_iterable(map(itemgetter(0, 4, 10), islice(r, 4, 10))), dtype=float).reshape(6, -1))
10000 loops, best of 3: 86 µs per loop