bash 脚本 - 使用选项而不是选项

Question

我在 bash 中创建了一个脚本来检查密码组合的强度 我想添加一个选项，用户可以从文本文件中输入密码（用户输入 -f，然后输入文件路径，然后他会获得密码审查），或者他输入密码之前没有任何选项

如果我想使用参数，我想问我需要做什么。 就像用户不使用文件来从文本文件中读取密码一样 他只是自己输入密码

#!/bin/bash
while getopts ":f:" option; do
      case $option in
             f) password=`cat $OPTARG` ;;
      esac
done
#evaluating how much chars the password has
password_length=${#password}
#counter for checking in how much sections the password meets the rquirements
count=0
#Creating an array for stroing reasons why the password is incorrect
requirements=(foo bar)
#Checking if password includes minimum of 10 characters
if [ $password_length -ge 10 ];
then
    requirements[0]="Correct"
else
    requirements[0]="Incorrect password syntax. The password
    length must includes minimum of 10 characters"
fi
#checkig if the password includes both alphabet and number
if [[ "$password" == *[a-zA-Z]* && "$password" == *[0-9]* ]]
then
    requirements[1]="Correct"
    
else
    requirements[1]="Incorrect password syntax. The password
    must includes both alphabet and number"
    
fi
#checking if password includes both the small and capital case letters.
if [[ "$password" == *[A-Z]* && "$password" == *[a-z]* ]];
then
    requirements[2]="Correct"
else
    requirements[2]="Incorrect password syntax. The password
    must includes both the small and capital case letters"
    
fi
#checking whether the password is according to the requirements or not 
#if yes count will equal to 3 at the end
for i in "${requirements[@]}"
do
    if [[ $i == "Correct" ]];
    then
        let count++
    fi
done
#if the counter count is equal to 3 print the password in light green color and return exit 0
if [[ $count -eq 3 ]];
then
    echo -e "\e[92m$password"
# sleep - user has the time to see that the password's syntax is correct 
    sleep 3
    exit 0 
#if the count is not equal to 3 print the password in reg color and return exit 1
else
    echo -e "\e[91m$password"
    for i in "${requirements[@]}"
    do
        if [[ $i != "Correct" ]];
        then
            echo $i        
        fi
    done
# sleep - user has the time to see that the password's syntax is incorrect and the reasons for that
    sleep 6
    exit 1
fi

那么在脚本中写什么来获取参数如果用户不使用选项将键入什么

Answer 1

通常，在 while getopts 循环之后，您希望 shift 关闭您刚刚处理的选项：

while getopts ":f:" option; do
      case $option in
             f) # bash builtin way to slurp a file into a variable 
                password=$(< "$OPTARG") ;;
      esac
done

# remove the options, if any
shift $((OPTIND - 1))


# the remaining command line arguments are at `$1`, `$2`, etc, as usual.
[[ -n $1 ]] && password=$1

如果您的用户指定both -f 选项并且 在命令行上提供密码，您想做什么？你想用哪一个？用我写的，命令行密码赢了。

另一种实现方式，其中-f 选项优先：

password_file=""
while getopts ":f:" option; do
      case $option in
             f) password_file=$OPTARG ;;
      esac
done
shift $((OPTIND - 1))

if [[ -n $password_file ]]; then
    if [[ ! -r $password_file ]]; then
        echo "Cannot read '$password_file'" >&2
        exit 1
    fi
    password=$(< "$password_file")
elif [[ -n $1 ]]; then
    password=$1
else
    echo "No password provided. Usage: ..." >&2
    exit 1
fi

Answer 2

检查password 变量是否已经设置。如果没有，请用户输入。

while getopts ":f:" option; do
    case $option in
        f) password=`cat $OPTARG` ;;
    esac
done
if [ -z "$password" ]
then read -p "Enter password: " -r password
fi