如何从数组中打开多个文本文件？

Question

我想打开并阅读几个文本文件。计划是在文本文件中找到一个字符串并从字符串中打印整行。问题是，我无法打开阵列中的路径。 我希望我想尝试的东西是不可理解的。

import os
from os import listdir
from os.path import join
from config import cred

path = (r"E:\Utorrent\Leaked_txt")
for filename in os.listdir(path):
    list = [os.path.join(path, filename)]
    print(list)

for i in range(len(list)-1):
    with open(str(list[i], "r")) as f:
        for line in f:
            if cred in line:
                print(line)

谢谢:D

Answer 1

我更喜欢在读取目录中的多个文件时使用 glob

import glob

files = glob.glob(r"E:\Utorrent\Leaked_txt\*.txt") # read all txt files in folder

for file in files: # iterate over files
    with open(file, 'r') as f: # read file
        for line in f.read(): # iterate over lines in each file
            if cred in line: # if some string is in line
                print(line) # print the line

Answer 2

使用os，您可以执行以下操作：

import os
from config import cred 

path = "E:/Utorrent/Leaked_txt"
files = [os.path.join(path, file) for file in os.listdir(path) if file.endswith(".txt")]

for file in files:
    with open(file, "r") as f:
        for line in f.readlines():
            if cred in line:
                print(line)

编辑

os.listdir 仅包含父目录中的文件（由path 指定）。要从所有子目录中获取 .txt 文件，请使用以下命令：

files = list()
for root, _, f in os.walk(path):
    files += [os.path.join(root, file) for file in f if file.endswith(".txt")]