带有 generate_from_frequencies 的 Wordcloud Python

Question

我正在尝试从 csv 文件创建 wordcloud。以csv文件为例，其结构如下：

a,1
b,2
c,4
j,20

它有更多的行，或多或少 1800。第一列有字符串值（名称），第二列有它们各自的频率（int）。然后，读取文件并将键值行存储在字典 (d) 中，因为稍后我们将使用它来绘制 wordcloud：

reader = csv.reader(open('namesDFtoCSV', 'r',newline='\n'))
d = {}
for k,v in reader:
    d[k] = v

一旦我们有了充满值的字典，我就会尝试绘制 wordcloud：

#Generating wordcloud. Relative scaling value is to adjust the importance of a frequency word.
#See documentation: https://github.com/amueller/word_cloud/blob/master/wordcloud/wordcloud.py
    wordcloud = WordCloud(width=900,height=500, max_words=1628,relative_scaling=1,normalize_plurals=False).generate_from_frequencies(d)
    plt.imshow(wordcloud, interpolation='bilinear')
    plt.axis("off")
    plt.show()
But an error is thrown:

    Traceback (most recent call last):
    File ".........../script.py", line 19, in <module>
    wordcloud = WordCloud(width=900,height=500, max_words=1628,relative_scaling=1,normalize_plurals=False).generate_from_frequencies(d)
    File "/usr/local/lib/python3.5/dist-packages/wordcloud/wordcloud.py", line  360, in generate_from_frequencies
    for word, freq in frequencies]
    File "/usr/local/lib/python3.5/dist-packages/wordcloud/wordcloud.py", line 360, in <listcomp>
    for word, freq in frequencies]
    TypeError: unsupported operand type(s) for /: 'str' and 'float

最后，文档说：

def generate_from_frequencies(self, frequencies, max_font_size=None):
    """Create a word_cloud from words and frequencies.
    Parameters
    ----------
    frequencies : dict from string to float
        A contains words and associated frequency.
    max_font_size : int
        Use this font-size instead of self.max_font_size
    Returns
    -------
    self
```python

So, I don't understand why is trowing me this error if I met the requirements of the function. I hope someone can help me, thanks.

**Note**

I work with worldcloud 1.3.1

Answer 1

这是因为字典中的值是字符串，但 wordcloud 需要整数或浮点数。

在我运行您的代码后，检查您的字典 d 我得到以下信息。

In [12]: d

Out[12]: {'a': '1', 'b': '2', 'c': '4', 'j': '20'}

注意数字周围的' ' 表示这些确实是字符串。

解决此问题的一种巧妙方法是将v 转换为int 在您的FOR 循环中，例如：

d[k] = int(v)

我说这是 hacky，因为它适用于整数，但如果你的输入中有浮点数，那么它可能会导致问题。

此外，Python 错误可能难以阅读。您上面的错误可以解释为

script.py", line 19

TypeError: unsupported operand type(s) for /: 'str' and 'float

“在我的文件的第 19 行或之前有一个类型错误。让我看看 我的数据类型，看看字符串和 浮动...”

下面的代码对我有用：

import csv
from wordcloud import WordCloud
import matplotlib.pyplot as plt

reader = csv.reader(open('namesDFtoCSV', 'r',newline='\n'))
d = {}
for k,v in reader:
    d[k] = int(v)

#Generating wordcloud. Relative scaling value is to adjust the importance of a frequency word.
#See documentation: https://github.com/amueller/word_cloud/blob/master/wordcloud/wordcloud.py
wordcloud = WordCloud(width=900,height=500, max_words=1628,relative_scaling=1,normalize_plurals=False).generate_from_frequencies(d)

plt.imshow(wordcloud, interpolation='bilinear')
plt.axis("off")
plt.show()

Answer 2

# LEARNER CODE START HERE
file_c=""
for index, char in enumerate(file_contents):
    if(char.isalpha()==True or char.isspace()):
        file_c+=char
file_c=file_c.split()
file_w=[]
for word in file_c:
    if word.lower() not in uninteresting_words and word.isalpha()==True:
    file_w.append(word)
frequency={}
for word in file_w:
    if word.lower() not in frequency:
        frequency[word.lower()]=1
    else:
        frequency[word.lower()]+=1
#wordcloud
cloud = wordcloud.WordCloud()
cloud.generate_from_frequencies(frequency)
return cloud.to_array()