如何正确计算字符串中有多少个小写、大写和其他字符？

Question

我的代码在这里表示所有小写和大写字母的计数，但我无法计算所有其他字符。其他字符由空格和符号组成，例如 '!@$^%$'。任何不是小写或大写的都指其他。

但是，我的问题是我的另一个是大写字母，我似乎无法计算出代码。

我不知道我哪里出错了，所以任何帮助将不胜感激，谢谢！

Console.WriteLine("Enter a sentence: ");
string sentence = Console.ReadLine();
int countUpper = 0, countLower=0, countOther=0, i;



        for (i = 0; i < sentence.Length;i++ )
        {
            if (char.IsUpper(sentence[i])) countUpper++;
            if (char.IsLower(sentence[i])) countLower++;
            if (!(char.IsLower(sentence[i]) || (!(char.IsUpper(sentence[i]))))) countOther++;

        }
        Console.WriteLine("Lower: " + countLower);
        Console.WriteLine("Upper: " + countUpper);
        Console.WriteLine("Other: " + countOther);

Answer 1

尝试改用if / else if / else：

Console.WriteLine("Enter a sentence: ");
string sentence = Console.ReadLine();
int countUpper = 0, countLower=0, countOther=0, i;



        for (i = 0; i < sentence.Length;i++ )
        {
            if (char.IsUpper(sentence[i])) countUpper++;
            else if (char.IsLower(sentence[i])) countLower++;
            else countOther++;

        }
        Console.WriteLine("Lower: " + countLower);
        Console.WriteLine("Upper: " + countUpper);
        Console.WriteLine("Other: " + countOther);

Answer 2

要计算特定字符，可以使用简单的Regex 代替逐个字符分析：

string sentence = "testTESTING@,";
int countLower = Regex.Matches(sentence, @"\p{Ll}").Count;
int countUpper = Regex.Matches(sentence, @"\p{Lu}").Count;
int countOther = Regex.Matches(sentence, @"\W").Count;

// \p{category} - In that Unicode category
// category = Lu - Letter, uppercase
// category = Ll - letter, lowercase
// \W = non word character

简单规范《.Net框架正则表达式快速参考》可从http://www.microsoft.com/en-us/download/details.aspx?id=43119下载

Answer 3

我认为countOther 就是string.Length - countUpper - countLower。