尝试使用mysql在第一个字母上以大写开头的单词答案

【问题标题】：trying to get the word with starting upper case on first letter using mysql尝试使用mysql在第一个字母上以大写开头的单词
【发布时间】：2011-10-09 07:03:19
【问题描述】：

我有

              Visit table 
                 Visit_Id
                 Visit_Date values(09-09-2011)
                 Visit_status values like (accepted , refused)
                member_Id

我这样做是为了获得访问次数通过使用以下查询

SELECT visit_Status as Status, COUNT('x') AS Visits
                              FROM visits
                              WHERE visit_Date BETWEEN '2011-06-20' AND '2011-07-20'
                              GROUP BY visit_Status

它给出了这样的结果

                Status          Visits
                accepted         2
                refused          4

我能得到这样的结果吗

                Status          Visits

                Accepted         2
                Refused          4


      with upper case letter on first letter of status i mean like this ( Accepted , Refused) instead of this one  (accepted , refused)

我正在使用mysql工作台

【问题讨论】：

标签： mysql sql mysql-workbench uppercase

【解决方案1】：

你可以使用SUBSTRING和UPPER

select CONCAT(UPPER(SUBSTRING(visit_Status, 1, 1)), 
      LOWER(SUBSTRING(visit_Status FROM 2))) as Status ......

【讨论】：

【解决方案2】：

这会做你想做的事：

SELECT CONCAT(UPPER(SUBSTRING(Visit_status, 1, 1)), LOWER(SUBSTRING(Visit_status FROM 2))) AS Status COUNT('x') AS Visits
       FROM visits
      WHERE visit_Date BETWEEN '2011-06-20' AND '2011-07-20'
      GROUP BY visit_Status

【讨论】：

【解决方案3】：

SELECT CONCAT(UPPER(SUBSTRING(Visit_status, 1, 1)), SUBSTRING(Visit_status FROM 2)) as Status, COUNT('x') AS Visits
FROM visits
WHERE visit_Date BETWEEN '2011-06-20' AND '2011-07-20'
GROUP BY visit_Status

【讨论】：