使用 regex 删除首字母缩写词，基于括号后的大写字符答案

【问题标题】：Removing acronyms using regex , based on uppercase characters following parenthesis使用 regex 删除首字母缩写词，基于括号后的大写字符
【发布时间】：2021-07-26 18:53:58
【问题描述】：

如何删除以下内容：

首字母缩写词以左括号开头，后跟大写或号码：例如'(ABC' 或 '(ABC)' 或 '(ABC-2A)' 或 '(ABC-1)'。

但NOT括号之间的单词以大写开头，后跟小写，例如'(Bobby)' 或 '(Bob went to the beach..)' --> 这是我正在努力解决的部分。


text = ['(ABC went to the beach', 'The girl (ABC-2A) is walking', 'The dog (Bobby) is being walked', 'They are there (ABC)' ]
for string in text:
  cleaned_acronyms = re.sub(r'\([A-Z]*\)?', '', string)
  print(cleaned_acronyms)

#current output:
>> 'went to the beach' #Correct
>>'The girl -2A) is walking' #Not correct
>>'The dog obby) is being walked' #Not correct
>>'They are there' #Correct


#desired & correct output:
>> 'went to the beach'
>>'The girl is walking'
>>'The dog (Bobby) is being walked' #(Bobby) is NOT an acronym (uppercase+lowercase)
>>'They are there'

【问题讨论】：

标签： python regex string uppercase re

【解决方案1】：

使用模式\([A-Z0-9\-]+\)

例如：

import re

text = ['ABC went to the beach', 'The girl (ABC-2A) is walking', 'The dog (Bobby) is being walked', 'They are there (ABC)' ]
ptrn = re.compile(r"\([A-Z0-9\-]+\)")
for i in text:
    print(ptrn.sub("", i))

输出：

ABC went to the beach
The girl  is walking
The dog (Bobby) is being walked
They are there

【讨论】：

看起来你在这里得到了错误的样本数据。第一个元素以(ABC 开头，没有右括号。
哦...我以为是错字

【解决方案2】：

在以下上下文中使用\([A-Z\-0-9]{2,}\)?：

import re

text = ['(ABC went to the beach', 'The girl (ABC-2A) is walking', 'The dog (Bobby) is being walked', 'They are there (ABC)' ]
for string in text:
  cleaned_acronyms = re.sub(r'\([A-Z\-0-9]{2,}\)?', '', string)
  print(cleaned_acronyms)

我得到了这些结果：

' went to the beach'
'The girl  is walking'
'The dog (Bobby) is being walked'
'They are there '

【讨论】：

您可能还想捕捉空格以获得更好的结果，就像在 OP 中一样。 =) ++
我意识到，但是在看到您的答案比我自己的答案好得多之后，我决定尝试从您那里获取“最佳答案”是自私的。干得好！
不要担心这样的事情。改善您的答案，让 OP 决定哪些答案最适合他。不要自暴自弃！
你的两个答案都很棒。非常感谢您的努力！

【解决方案3】：

尝试否定前瞻：

\((?![A-Z][a-z])[A-Z\d-]+\)?\s*

在线查看demo

\( - 文字开头的括号。
(?![A-Z][a-z]) - 否定前瞻断言位置不跟随大写跟随小写。
[A-Z\d-]+ - 匹配 1+ 个大写字母字符、数字或连字符。
\)? - 可选的文字结束括号。
\s* - 0+ 个空格字符。

一些示例 Python 脚本：

import re
text = ['(ABC went to the beach', 'The girl (ABC-2A) is walking', 'The dog (Bobby) is being walked', 'They are there (ABC)' ]
for string in text:
  cleaned_acronyms = re.sub(r'\((?![A-Z][a-z])[A-Z\d-]+\)?\s*', '', string)
  print(cleaned_acronyms)

打印：

went to the beach
The girl is walking
The dog (Bobby) is being walked
They are there

【讨论】：

所有答案都非常有帮助。我接受了你的解释，因为你对每个部分都做了解释，这真的有助于我理解。