【发布时间】:2014-07-01 09:26:29
【问题描述】:
嗨,我在 mysql phpMyAdmin 中创建表时遇到 1022 错误。 错误在最后一个表“usercomment”上:
解决方案编辑:好的,我已经有一个名为 IdMovie 的约束键,所以我重命名了它,它工作正常。
谢谢各位。
这是表格:
CREATE TABLE IF NOT EXISTS `WhichMovie`.`UserComent` (
`IDComent` INT NOT NULL,
`IDUser` INT NOT NULL,
`IDMovie` INT NOT NULL,
`date` TIMESTAMP NOT NULL,
PRIMARY KEY (`IDComent`, `IDUser`, `IDMovie`, `date`),
INDEX `idUser_idx` (`IDUser` ASC),
INDEX `idMovie_idx` (`IDMovie` ASC),
CONSTRAINT `IdComent`
FOREIGN KEY (`IDComent`)
REFERENCES `WhichMovie`.`Coment` (`idComent`)
ON DELETE CASCADE
ON UPDATE CASCADE,
CONSTRAINT `IiUser`
FOREIGN KEY (`IDUser`)
REFERENCES `WhichMovie`.`User` (`idUser`)
ON DELETE CASCADE
ON UPDATE CASCADE,
CONSTRAINT `IdMovie`
FOREIGN KEY (`IDMovie`)
REFERENCES `WhichMovie`.`Movie` (`idMovie`)
ON DELETE CASCADE
ON UPDATE CASCADE)
ENGINE = InnoDB;
-- -----------------------------------------------------
-- Table `WhichMovie`.`Movie`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `WhichMovie`.`Movie` (
`idMovie` INT NOT NULL AUTO_INCREMENT,
`Ttle` VARCHAR(45) NULL,
`Year` INT NULL,
`Country` VARCHAR(45) NULL,
`Poster` BLOB NULL,
`Rating` DECIMAL NULL,
PRIMARY KEY (`idMovie`))
ENGINE = InnoDB;
-- -----------------------------------------------------
-- Table `WhichMovie`.`User`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `WhichMovie`.`User` (
`idUser` INT NOT NULL AUTO_INCREMENT,
`Username` VARCHAR(45) NOT NULL,
`Email` VARCHAR(45) NOT NULL,
`Country` VARCHAR(45) NULL,
`Pass` VARCHAR(45) NOT NULL,
PRIMARY KEY (`idUser`, `Username`, `Email`),
UNIQUE INDEX `idUser_UNIQUE` (`idUser` ASC),
UNIQUE INDEX `Email_UNIQUE` (`Email` ASC),
UNIQUE INDEX `Username_UNIQUE` (`Username` ASC))
ENGINE = InnoDB;
-- -----------------------------------------------------
-- Table `WhichMovie`.`Coment`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `WhichMovie`.`Coment` (
`idComent` INT NOT NULL AUTO_INCREMENT,
`NameComent` VARCHAR(45) NULL,
PRIMARY KEY (`idComent`),
UNIQUE INDEX `idComent_UNIQUE` (`idComent` ASC))
ENGINE = InnoDB;
谁能看到?
【问题讨论】:
-
需要查看引用的表定义。
-
您还应该向我们提供 UserComment 引用的其他表结构
-
看来问题不在于结构。创建表和插入数据我没有问题。您是否 100% 确定问题不是在插入数据时出现的?重命名您的 whichmovie 数据库,创建空的 whichmovie 数据库,然后按照我的答案导入这些查询。当您在创建表时启动这些查询时,您真的会看到错误吗?
标签: mysql