【发布时间】:2012-07-07 22:33:29
【问题描述】:
是否有人知道将 Play 框架与 SLICK (ScalaQuery) 结合使用的好教程或示例项目 (github)?我正在努力让它们一起工作。
我收到此错误:
[info] play - Application started (Dev)
[error] application -
! @6b13oi41c - Internal server error, for request [GET /listBooks] ->
play.core.ActionInvoker$$anonfun$receive$1$$anon$1: Execution exception [[NoClassDefFoundError: Could not initialize class scala.slick.ast.opt.Relational$]]
at play.core.ActionInvoker$$anonfun$receive$1.apply(Invoker.scala:134) [play_2.9.1-2.0.2.jar:2.0.2]
at play.core.ActionInvoker$$anonfun$receive$1.apply(Invoker.scala:115) [play_2.9.1-2.0.2.jar:2.0.2]
at akka.actor.Actor$class.apply(Actor.scala:318) [akka-actor-2.0.2.jar:2.0.2]
at play.core.ActionInvoker.apply(Invoker.scala:113) [play_2.9.1-2.0.2.jar:2.0.2]
at akka.actor.ActorCell.invoke(ActorCell.scala:626) [akka-actor-2.0.2.jar:2.0.2]
at akka.dispatch.Mailbox.processMailbox(Mailbox.scala:197) [akka-actor-2.0.2.jar:2.0.2]
Caused by: java.lang.NoClassDefFoundError: Could not initialize class scala.slick.ast.opt.Relational$
at scala.slick.driver.BasicProfile$class.processAST(BasicProfile.scala:18) ~[slick_2.10.0-M4-0.10.0-M2.jar:0.10.0-M2]
at scala.slick.driver.PostgresDriver$.processAST(PostgresDriver.scala:69) ~[slick_2.10.0-M4-0.10.0-M2.jar:0.10.0-M2]
at scala.slick.driver.BasicProfile$class.createQueryBuilder(BasicProfile.scala:22) ~[slick_2.10.0-M4-0.10.0-M2.jar:0.10.0-M2]
at scala.slick.driver.PostgresDriver$.createQueryBuilder(PostgresDriver.scala:69) ~[slick_2.10.0-M4-0.10.0-M2.jar:0.10.0-M2]
at scala.slick.driver.BasicProfile$class.buildSelectStatement(BasicProfile.scala:23) ~[slick_2.10.0-M4-0.10.0-M2.jar:0.10.0-M2]
at scala.slick.driver.PostgresDriver$.buildSelectStatement(PostgresDriver.scala:69) ~[slick_2.10.0-M4-0.10.0-M2.jar:0.10.0-M2]
[error] application -
这是我的 Book 模型:
package models
import play.api.db._
import play.api.Play.current
import scala.slick.driver.PostgresDriver.simple._
import scala.slick.ql.{MappedTypeMapper}
import scala.slick.session.{Session, Database}
case class Book(name: String, filename: String)
object Book extends Table[(Long, String, String)]("book") {
lazy val database = Database.forDataSource(DB.getDataSource())
def id = column[Long]("id", O PrimaryKey, O AutoInc)
def name = column[String]("name", O NotNull)
def filename = column[String]("filename", O NotNull)
def * = id ~ name ~ filename
def findAll() : Seq[Book] = database.withSession { implicit db:Session =>
(for(t <- this) yield t.name ~ t.filename).list.map(attrs => Book(attrs._1, attrs._2))
}
def create(book: Book): Unit = database.withSession { implicit db:Session =>
this.name ~ this.filename insert(book.name, book.filename)
}
}
编辑:
这是我的 Build.scala
import sbt._
import Keys._
import PlayProject._
object ApplicationBuild extends Build {
val appName = "PlayWithScala"
val appVersion = "1.0-SNAPSHOT"
val appDependencies = Seq(
// Add your project dependencies here,
"postgresql" % "postgresql" % "9.1-902.jdbc4",
"com.typesafe" % "slick_2.10.0-M4" % "0.10.0-M2"
)
val main = PlayProject(appName, appVersion, appDependencies, mainLang = SCALA).settings(
// Add your own project settings here
)
}
【问题讨论】:
-
推测:这看起来像是类路径问题。
-
请出示您的 Build.scala 文件。
-
@nico_ekito,用 Build.scala 更新了我的问题。
-
@pedrofurla,是的,正如您所见,我对 Scala 和 play 框架都是新手,我不确定 CLASSPATH 中包含哪些目录。
-
看看这篇博文:blogeek.com.ar/2012/11/24/…
标签: scala playframework-2.0 scalaquery