Array 删除数字的最后 2 位数字

Question

我想创建一个程序，输入一个数字，例如：12345，然后将此数字拆分为2位数字并将其存储在一个数组中。数组必须如下所示： [0]=45 [1]=23 [2]=1 。这意味着数字的拆分必须从数字的最后一位而不是第一位开始。

这是我到现在为止的：

var splitCount = []; // This is the array in which we store our split numbers
//Getting api results via jQuery's GET request
$.get("https://www.googleapis.com/youtube/v3/channels?part=statistics&id=UCJwchuXd_UWNxW-Z1Cg-liw&key=AIzaSyDUzfsMaYjn7dnGXy9ZEtQB_CuHyii4poc", function(result) {
    //result is our api answer and contains the recieved data
    //now we put the subscriber count into another variable (count); this is just for clarity
    count = result.items[0].statistics.subscriberCount;
    //While the subscriber count still has characters
    while (count.length) {
        splitCount.push(count.substr(0, 2)); //Push first two characters into the splitCount array from line 1
        count = count.substr(2); //Remove first two characters from the count string
    }       
    console.log(splitCount) //Output our splitCount array
});

但问题在于，如果有 5 个数字，例如：12345，最后一个数字将单独存在于一个数组中，如下所示：[0]=12 [1]=34 [2]=5 但我需要最后一个数组有 2 个数字，第一个应该是一个数字，而不是像这样：[0]=1 [1]=23 [2]=45

Answer 1

我可能会这样做：

int[] fun(int x){
   int xtmp = x;
   int i = 0;
   int len = String.valueOf(x).length(); 
   // this is a function for java, but you can probably find 
   //an equivalent in whatever language you use
   int tab[(len+1)/2];
   while(xtmp > 1){
       tab[i] = xtmp%100;
       xtmp = int(xtmp/100); // here you take the integer part of your xtmp
       ++i;
   }
   return tab;
}

Answer 2

非常粗略，但假设字符串始终是数字，这应该可以工作：

input = "12345"

def chop_it_up(input)
  o = []

  while input.length > 0
    if input.length <= 2
      o << input
    else
      o << input[-2..input.length]
    end
    input = input[0..-3]
    chop_it_up(input)
  end

  return o
end