在 Rust 中第 n 次出现字符时拆分字符串

Question

如何在 Rust 中第 N 次出现字符时拆分字符串？

另见：

• Split string at nth occurrence of a given character (Python)
• Cutting a string at nth occurrence of a character (Javascript)
• Find Nth occurrence of a character in a string (C#)
• How can I split a string in PHP at the nth occurrence of a needle? (PHP)

Answer 1

您可以使用match_indices() 获取位置，然后使用split_at() 拆分字符串。如果您想排除实际字符，它有点复杂，但您可以使用char_indices() 跳过一个。这感觉有点重，但我找不到更简单的方法。

/// Search `s` for the `n`th occurrence of `p`, then split the string
/// into two halves around that point.
fn split_at_nth_char(s: &str, p: char, n: usize) -> Option<(&str, &str)> {
    s.match_indices(p).nth(n).map(|(index, _)| s.split_at(index))
}

/// Same as `split_at_nth_char` but don't include the character.
fn split_at_nth_char_ex(s: &str, p: char, n: usize) -> Option<(&str, &str)> {
    split_at_nth_char(s, p, n).map(|(left, right)| {
        (
            left,
            // Trim 1 character.
            &right[right.char_indices().nth(1).unwrap().0..],
        )
    })
}

fn main() {
    dbg!(split_at_nth_char("this/is/a/string", '/', 1));
    dbg!(split_at_nth_char("this/is/a/string", '/', 2));
    dbg!(split_at_nth_char("this/is/a/string", '/', 3));
    dbg!(split_at_nth_char_ex("this/is/a/string", '/', 1));
}

输出：

[src/main.rs:19] split_at_nth_char("this/is/a/string", '/', 1) = Some(
    (
        "this/is",
        "/a/string",
    ),
)
[src/main.rs:20] split_at_nth_char("this/is/a/string", '/', 2) = Some(
    (
        "this/is/a",
        "/string",
    ),
)
[src/main.rs:21] split_at_nth_char("this/is/a/string", '/', 3) = None
[src/main.rs:22] split_at_nth_char_ex("this/is/a/string", '/', 1) = Some(
    (
        "this/is",
        "a/string",
    ),
)