如何将公共函数返回字符串用于同一类中的变量？ PHP 类

Question

我正在尝试在类名“settings”中使用函数“get_setting”返回的字符串。我想将返回的字符串用于变量“top_banner”。当我尝试使用 '$this' 变量来访问该函数时，它不起作用。

class settings{

 function get_setting($name, $return="value"){
    $query = mysql_query("SELECT * FROM website_settings WHERE name='".$name."'");
    $row = mysql_fetch_array($query);
    if($row['active'] == false){//This is turned off
        return "disabled";
    }else{//this setting is active
        return $row['value'];
    }

}
    //Values
public $top_banner = $this->get_setting("top_banner");
}

Answer 1

试试这个：

class settings{

 function get_settings($name, $return="value"){
    $query = mysql_query("SELECT * FROM website_settings WHERE name='".$name."'");
    $row = mysql_fetch_array($query);
    if($row['active'] == false){//This is turned off
        return "disabled";
    }else{//this setting is active
        return $row['value'];
    }

   }
}
  //Values
$my_settings = new settings();
$top_banner = $my_settings->get_settings("top_banner");