使用Javascript以任何顺序使用正则表达式查找字符串中的所有匹配项

Question

我如何在下面找到所有匹配项？我现在的方法是从关键字数组中找到 any 匹配项，但是，由于存在单词“not”，因此在控制台中匹配项应该为空。

var title = "How to edit an image";
var keywords = ["image","edit","not"];
var matches = [];
if (title.search(new RegExp(keywords.join("|"),"i")) != -1) {
     matches.push(title);
}
console.log(matches);

Answer 1

不需要正则表达式，只需使用 every() 遍历单词，然后使用 includes() 检查每个关键字（见下文）；

console.log(Check("How to edit an image", ["image","edit","not"])); // false
console.log(Check("How to edit an image", ["image","edit"]));       // true

function Check(title, keywords) {
    return keywords.every(word => title.indexOf(word) > -1);
}

注意：使用title.indexOf(word) > -1 支持 IE 11 作为 OP 请求。

---

编辑；基于OP的评论；

_{从keywords 数组中删除"not" 以确保逻辑有效}

var title = "How to edit an image";
var keywords = ["image","edit","not"];
var matches = [];
if (keywords.every(word => title.indexOf(word) > -1)) {
     matches.push(title);
}
console.log(matches);

Answer 2

你不需要正则表达式。只需映射关键字

const output= keywords.map(x=>
    title.indexOf(x)!==-1 ? title : ""
);

//output
["How to edit an image", "How to edit an image", ""]

Answer 3

使用这个answer作为参考，如果你固定使用Regex，你应该使用lookarounds：

^(?=.*\bimage\b)(?=.*\bedit\b)(?=.*\bnot\b).*$

应用在您的 Javascript 代码上，它会是这样的：

var title = "How to edit an image";
var title2 = "How to not edit an image";
var keywords = ["image","edit","not"];
var matches = [];

// Using for block because I don't remember if forof, forin or foreach are supported by IE 11
var regex = "^";
for (var i = 0; i < keywords.length; i++) {
    regex += "(?=.*\\b" + keywords[i] + "\\b)"; // Needed beacuse template Strings are not supported by IE 11.
}
regex += ".*$"

if (title.search(new RegExp(regex,"i")) != -1) {
    matches.push(title);
}
console.log(matches);

if (title2.search(new RegExp(regex,"i")) != -1) {
    matches.push(title2);
}
console.log(matches);