【问题标题】:TypeError: get() takes 1 positional argument but 3 were givenTypeError: get() 接受 1 个位置参数,但给出了 3 个
【发布时间】:2015-09-01 17:51:57
【问题描述】:

此代码将通过tkinter 运行一个基本数据输入窗口,该窗口将保存用户的输入。当我运行代码并鼠标单击提交按钮时,我收到错误:

print ("Información Adicional: {}".format(self.entry_name.get(1.0, "end")))

TypeError: get() takes 1 positional argument but 3 were given

这是代码:

import tkinter
from tkinter import *
from tkinter import ttk
from tkinter import messagebox

class ImprintPlusApp:

    def __init__(self, master):
        self.frame_header = ttk.Frame(master)
        self.frame_header.pack()

        ttk.Label(self.frame_header, text = "Bienvenidos a Imprint Plus Manager")

        self.frame_crearorden = ttk.Frame(master)
        self.frame_crearorden.pack()

        ttk.Label(self.frame_crearorden, text = "Nombre").grid(row = 0, column = 0, padx = 5)
        ttk.Label(self.frame_crearorden, text = "Email").grid(row = 2, column = 0, padx = 5)
        ttk.Label(self.frame_crearorden, text = "Numero Cel/Tel").grid(row = 4, column = 0, padx = 5)
        ttk.Label(self.frame_crearorden, text = "Información Adicional").grid(row = 6, column = 0, padx = 5)

        self.entry_name = ttk.Entry(self.frame_crearorden, width = 24)
        self.entry_email = ttk.Entry(self.frame_crearorden, width = 24)
        self.entry_numtc = ttk.Entry(self.frame_crearorden, width = 24)
        self.entry_addinf = Text(self.frame_crearorden, width = 50, height = 10)

        self.entry_name.grid(row = 0, column = 1, padx = 5)
        self.entry_email.grid(row = 2, column = 1, padx = 5)
        self.entry_numtc.grid(row = 4, column = 1, padx = 5)
        self.entry_addinf.grid(row = 7, column = 0, columnspan = 2, padx = 5)

        ttk.Button(self.frame_crearorden, text = "Submit", command = self.submit).grid(row = 8, column = 1,columnspan = 1, padx = 5)
        ttk.Button(self.frame_crearorden, text = "Clear", command = self.clear).grid(row = 8, columnspan = 1, padx = 5)

    def submit(self):
        print ("Nombre: {}".format(self.entry_name.get()))
        print ("Email: {}".format(self.entry_name.get()))
        print ("Num Cel/Tel: {}".format(self.entry_name.get()))
        print ("Información Adicional: {}".format(self.entry_name.get(1.0, "end")))
        self.clear()
        messagebox.showinfo(title = "Orden #", message = "Orden Guardada")

    def clear(self):
        self.entry_name.delete(0, "end")
        self.entry_email.delete(0, "end")
        self.entry_numtc.delete(0, "end")
        self.entry_addinf.delete(1.0, "end")


def main():
    root = Tk()
    app = ImprintPlusApp(root)
    root.mainloop()

if __name__ == '__main__':
    main() 

导致此错误的get() 函数发生了什么?

【问题讨论】:

  • Entry.get dict.get...

标签: python tkinter


【解决方案1】:

我不确定您要做什么,但这是导致错误的行,错误消息清楚地表明了这一点 -

print ("Información Adicional: {}".format(self.entry_name.get(1.0, "end")))

你需要做的-

print ("Información Adicional: {}".format(self.entry_name.get()))

因为 Tkinter.Entry 类的 get() 函数不接受任何参数。

同样看代码,好像有逻辑问题-

def submit(self):
        print ("Nombre: {}".format(self.entry_name.get()))
        print ("Email: {}".format(self.entry_name.get()))
        print ("Num Cel/Tel: {}".format(self.entry_name.get()))
        print ("Información Adicional: {}".format(self.entry_name.get(1.0, "end")))

您不想从不同的Entry 对象中获取每个条目吗?像这样-

def submit(self):
        print ("Nombre: {}".format(self.entry_name.get()))
        print ("Email: {}".format(self.entry_email.get()))
        print ("Num Cel/Tel: {}".format(self.entry_numtc.get()))
        print ("Información Adicional: {}".format(self.entry_addinf.get()))

【讨论】:

  • 这解决了我的主要问题。我不敢相信我在入口对象上犯了这样一个逻辑错误,我猜它是在凌晨 4 点编码。非常感谢先生!
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