Javascript 对象映射（展平）答案

【问题标题】：Javascript Object Map (flatten)Javascript 对象映射（展平）
【发布时间】：2016-06-27 11:43:44
【问题描述】：

您好，我有一个使用 JSON.Stringify 输出到此的对象

{"0":["test1","ttttt","","","","","","","",""],"1":["test2","ghjgjhgjh","","","","","","","",""]}

我想要这样的输出。

[["test1","ttttt","","","","","","","",""],["test2","ghjgjhgjh","","","","","","","",""]]

我已经尝试使用 .map 删除“0”和“1”

var itemjson = $.map(cleanedGridData, function (n) {
        return n;
    });

然而，这给出了（下面）的输出，它已经变平了。

["test1", "ttttt", "", "", "", "", "", "", "", "", "test2", "ghjgjhgjh", "", "", "", "", "", "", "", ""]

【问题讨论】：

标签： javascript object dictionary flatten

【解决方案1】：

您可以使用它来提取值：

var res = {"0":["test1","ttttt","","","","","","","",""],"1":["test2","ghjgjhgjh","","","","","","","",""]}
Object.keys(res).map(function(key) {
    return res[key];
});

Object.keys 将列出初始对象中的所有键。然后，您可以使用 map 遍历这些键并在该函数中提取值。

【讨论】：

我确实喜欢不需要 jquery 的解决方案 :)

【解决方案2】：

更改您的 return 语句，将 n 放在另一个数组中。

return [n];

这是因为 jQuery 的 $.map 将你返回的数组展平成结果，所以你需要将它包裹在一个外部数组中。

要么这样，要么只使用for in 循环。

var itemjson = [];
for (var key in cleanedGridData) {
  itemjson.push(cleanedGridData[key]);
}

【讨论】：

【解决方案3】：

一旦您的环境（即对于您想要支持的所有浏览器）有Object.values（和spread operator）可用，您就可以使用

[...Object.values(cleanedGridData)]

【讨论】：