需要帮助在特定索引中对混合字符串和整数的嵌套数组进行排序

Question

我在那儿，

我有一个分数嵌套数组，我正在尝试对其进行排序，但是所有值都是字符串，并且排序如预期的那样混乱。

也全部保存在本地存储中。

我有下面的排序代码，它工作正常，但仅适用于第一个字符，所以对于索引 [3] 排序，例如我得到：

0000, 126, 15, 16, 20, 4, 4, 4, 5, 8 //如下面的数组所示。

但我应该得到：

0000、4、4、4、5、8、15、16、20、126

我读到我可以在排序之前添加零，然后在排序之后删除它们。但我想不出一种在如此复杂的数据数组中添加零的方法......

数组如下所示：

0: (5) ["Jack 9", "words", "6", "0000", "00:08:21"]
1: (5) ["Jack 6", "words", "59", "126", "00:08:22"]
2: (5) ["Jack 1", "words", "30", "15", "00:03:81"]
3: (5) ["Jack 4", "words", "24", "16", "00:02:94"]
4: (5) ["Jack 2", "words", "9",  "20", "00:14:90"]
5: (5) ["Jack 11","words", "9",   "4", "00:18:04"]
6: (5) ["Jack 10","words", "9",   "4", "00:19:06"]
7: (5) ["Jack 5", "words", "6",   "4", "00:08:97"]
8: (5) ["Jack 8", "words", "9",   "5", "00:16:83"]
9: (5) ["Jack 7", "words", "8",   "8", "00:19:98"]

function sortScoresErrors(array){
    array.sort((function(index){
        return function(a, b){
            return (a[index] === b[index] ? 0 : (a[index] < b[index] ? -1 : 1));
        };
        })(3));// (3) is the index - Descending
    };

Answer 1

您可以检查所需索引的值是否可以读取为数值并使用另一个函数与项目的增量进行比较。

function sortScoresErrors(array) {
    array.sort((function (index) {
        return isFinite(array[0][index])
            ? (a, b) => a[index] - b[index]
            : (a, b) => (a[index] === b[index] ? 0 : (a[index] < b[index] ? -1 : 1));
    })(3));
}

var data = [["Jack 9", "words", "6", "0000", "00:08:21"], ["Jack 6", "words", "59", "126", "00:08:22"], ["Jack 1", "words", "30", "15", "00:03:81"], ["Jack 4", "words", "24", "16", "00:02:94"], ["Jack 2", "words", "9", "20", "00:14:90"], ["Jack 11", "words", "9", "4", "00:18:04"], ["Jack 10", "words", "9", "4", "00:19:06"], ["Jack 5", "words", "6", "4", "00:08:97"], ["Jack 8", "words", "9", "5", "00:16:83"], ["Jack 7", "words", "8", "8", "00:19:98"]];

sortScoresErrors(data);

console.log(data);

.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 2

只需将字符串转换为条件中的数字即可。

替换return (a[index] === b[index] ? 0 : (a[index] < b[index] ? -1 : 1));

对此：return (Number(a[index]) === Number(b[index]) ? 0 : (Number(a[index]) < Number(b[index]) ? -1 : 1));

这在第三个索引中的字符串实际上是数字时有效