MySQL in() 多维数组

Question

以下工作（数组由另一个 MySQL 查询填充）：

$array=(1,4,5,6,8);
$query=SELECT * FROM table WHERE Id IN(".implode(",",$array)."

但是我该怎么做？：

$array=(
array('Id'=>1, 'Detail1'=>$row['Detail1'], 'Detail2'=>$row['Detail2']),
array('Id'=>4, 'Detail1'=>$row['Detail1'], 'Detail2'=>$row['Detail2']),
array('Id'=>5, 'Detail1'=>$row['Detail1'], 'Detail2'=>$row['Detail2']),
array('Id'=>6, 'Detail1'=>$row['Detail1'], 'Detail2'=>$row['Detail2']),
array('Id'=>8, 'Detail1'=>$row['Detail1'], 'Detail2'=>$row['Detail2']),
);
$query=SELECT * FROM table WHERE Id IN(".implode(",",$array[]['Id'])."

所以我需要获取所有的 id，我该如何在这个多维数组中做到这一点？

谢谢！

Answer 1

我会做这样的事情：

$id_list = array();

foreach($array as $item) {
 $id_list[] = $item['Id'];
}

$query = "SELECT * FROM table WHERE Id IN(".implode(',',$id_list).")";

Answer 2

另一种选择：

$list = array_reduce($id_list,function($total,$cur_value){
     if(!is_null($total)) $total .= ',';
     return $total.$cur_value['id'];
  });
$query = "SELECT * FROM table WHERE Id IN(".$list.")";