【发布时间】:2017-05-17 16:59:30
【问题描述】:
在我的应用程序中,我想暂时将数据添加到表布局中动态创建的表中,并通过 volley 将多行数据传递给 php mysql。 我不知道如何将动态表数据的值传递给数组..我可以在网站上使用 jQuery..通过这段代码。
var myTableArray = [];
$("table#myTable tr").each(function() {
var arrayOfThisRow = [];
var tableData = $(this).find('td');
if (tableData.length > 0) {
tableData.each(function() { arrayOfThisRow.push($(this).text()); });
myTableArray.push(arrayOfThisRow);}
在安卓中怎么做?
我的活动:
public class ArrayActivity extends AppCompatActivity {
EditText t1, t2,t3, t4;
Button btn;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_array);
t1 = (EditText) findViewById(R.id.id_01);
t2 = (EditText) findViewById(R.id.id_02);
t3 = (EditText) findViewById(R.id.id_03);
t4 = (EditText) findViewById(R.id.id_04);
btn = (Button) findViewById(R.id.id_btn);
final TextView textView = (TextView) findViewById(R.id.tv_101);
btn.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
String s1, s2, s3, s4;
s1 = t1.getText().toString();
s2 = t2.getText().toString();
s3 = t3.getText().toString();
s4 = t4.getText().toString();
TableLayout tableLayout = (TableLayout) findViewById(R.id.up_table);
TableRow row = new TableRow(ArrayActivity.this);
TextView t1v = new TextView(ArrayActivity.this);
t1v.setText(s1);
t1v.setGravity(Gravity.CENTER);
t1v.setBackgroundResource(R.drawable.row_border);
row.addView(t1v);
TextView t2v = new TextView(ArrayActivity.this);
t2v.setText(s2);
t2v.setGravity(Gravity.CENTER);
t2v.setBackgroundResource(R.drawable.row_border);
row.addView(t2v);
TextView t3v = new TextView(ArrayActivity.this);
t3v.setText(s3);
t3v.setGravity(Gravity.CENTER);
t3v.setBackgroundResource(R.drawable.row_border);
row.addView(t3v);
TextView t4v = new TextView(ArrayActivity.this);
t4v.setText(s4);
t4v.setGravity(Gravity.CENTER);
t4v.setBackgroundResource(R.drawable.row_border);
row.addView(t4v);
tableLayout.addView(row);
}
});
}
}
PHP 代码
<?php
$con = mysqli_connect('localhost', '******', '******', '******');
if ($con->connect_error) {
die("Connection failed: " . $con->connect_error);
}
$myTableArray = $_REQUEST['myTableArray'];
if(is_array($myTableArray)){
$aValues = array();
foreach ($myTableArray as $aRow) {
$aValues[] = "'" . implode("','", $aRow) . "'";
}
$sValues = "(" . implode("), (", $aValues) . ")";
$sql = "INSERT INTO mess (name, goods, quantity, price, action) values $sValues";
}
if ($con->query($sql) == TRUE) {
echo "Dear User, Data Added Successfully!";
} else {
echo "Error: " . $sql . "<br>" . $con->error;
}
$con->close();
?>
【问题讨论】:
-
澄清一下,您有一些 html 代码要解析成 Java 结构?你能提供一个输入的例子吗?
-
已添加 Java 和 php 代码。
标签: android json multidimensional-array android-volley tablelayout