使用 PHP 在多维数组上使用 array_map 更改键

Question

我使用 array_merge() 合并了 2 个具有相同信息但具有不同键的多维数组，我得到了输出：

   Array
   (
    [0] => Array
    (
        [Ttitle] => lilly
        [Price] => 1.75
        [Number] => 3
    )
    [1] => Array
    (
        [Title] => rose
        [Price] => 1.25
        [Number] => 15
    )
    [2] => Array
    (
        [Title] => daisy
        [Price] => 0.75
        [Number] => 25
    )
    [3] => Array
    (
        [Title] => nettle
        [Price] => 2.75
        [Number] => 33
    )
    [4] => Array
    (
        [Title] => orchid
        [Price] => 1.15
        [Number] => 7
    )
  )

如您所见，数组中的第一个键名是Ttitle，其余的是Title。我现在想要的是将所有Ttitle 键（目前只有一个）更改为Title（就像所有其他键一样）。当我使用array_map() 功能时，我设法将所有键更改为Title，但我也删除了所有Title 值，除了我刚刚更改为Ttitle 的Ttitle 键。

代码如下：

   if(! empty($notmatchingarray))
   {
    $completearray = array_merge($notmatchingarray, $datastuff2);

    $completearray = array_map(function($complete) {
        return array(
           'Title' => $complete['Ttitle'],
           'Price' => $complete['Price'],
           'Number' => $complete['Number'],
       );
}, $completearray);

echo "Array which includes each unique enrty from both arrays";
echo "<pre>";
print_r($completearray);
echo "</pre>";
echo "<br/>";
   }

这段代码的输出：

  Array
  (
  [0] => Array
    (
        [Title] => lilly
        [Price] => 1.75
        [Number] => 3
    )
  [1] => Array
    (
        [Title] => 
        [Price] => 1.25
        [Number] => 15
    )
  [2] => Array
    (
        [Title] => 
        [Price] => 0.75
        [Number] => 25
    )
  [3] => Array
    (
        [Title] => 
        [Price] => 2.75
        [Number] => 33
    )
  [4] => Array
    (
        [Title] => 
        [Price] => 1.15
        [Number] => 7
    )
  )

我在使用这个array_map() 函数时做错了吗？我应该做其他事情吗？

Answer 1

更好的方法，但我要走了。使用您现有的代码，您需要设置Ttitle 或Title，以存在者为准：

$completearray = array_map(function($complete) {
        $title = isset($complete['Ttitle']) ? $complete['Ttitle'] : $complete['Title'];
        return array(
           'Title' => $title,
           'Price' => $complete['Price'],
           'Number' => $complete['Number'],
       );
}, $completearray);

Ternary operator 是一个简单的if / else 的快捷方式，所以：

if(isset($complete['Ttitle'])) {
    $title = $complete['Ttitle']; //if Ttitle is set use it
} else {
    $title = $complete['Title'];  //if not use Title
}

Answer 2

您可以尝试使用array_key_exists 函数：

$completearray = array_map(function($complete) {
    return array(
       'Title' => (array_key_exists('Title', $complete) 
                   ? $complete['Title'] 
                   : $complete['Ttitle']),
       'Price' => $complete['Price'],
       'Number' => $complete['Number'],
   );
}, $completearray);

或者，如果您愿意：

$completearray = array_map(function($complete) {
    $titleKey = array_key_exists('Title', $complete) ? 'Title' : 'Ttitle';
    return array(
       'Title' => $complete[$titleKey],
       'Price' => $complete['Price'],
       'Number' => $complete['Number'],
   );
}, $completearray);

如果数组$complete 包含键'Title'，它将使用它；否则它将使用密钥'Ttitle'。