将ndarrays列表乘以列表

Question

我想将一个数字列表乘以一个 ndarray，即列表中的每个数字乘以第一个 ndarray。 这是列表：

list1 = [840,845,897]

这是 ndarray 的列表

list = df['Example']
list
0     [[nan, nan, nan, 0.854,nan,0.562,0.21615],[nan, nan, nan, 0.854,nan,0.562,0.21615]]
1     [[nan, nan, nan, nan, nan, nan, 0.5196,0.56518,0.165],[nan, nan, nan, nan, nan, nan, 0.816,0.5565518,0.225]
2     [[nan, nan, nan, nan, nan, nan, nan, 0.8528845],[nan, 0.595, nan, nan, 0.2651, nan, nan, 0.8528845],[nan, nan, nan, nan, nan, nan, nan, 0.8516]

我想将列表中的第一项乘以第一个 ndarray。 nan 值仍然是 nan 并且只是乘以浮点数。我尝试过使用 map、lambda 函数、for 迭代，但没有成功。我经常遇到的错误是：TypeError: can't multiply sequence by non-int of type 'str'。它可以使用新数据创建一个单独的列，或者只是创建一个列表。结果：

list_new
0     [[nan, nan, nan, 717.36,nan,472.08,181.566],[nan, nan, nan, 717.36,nan,472.08,181.5666]]
1     [[nan, nan, nan, nan, nan, nan, 439.062,477.5771,139.425],[nan, nan, nan, nan, nan, nan, 689.52,470.28,190.125]
2     [[nan, nan, nan, nan, nan, nan, nan, 765.037],[nan, 533.715, nan, nan, 237.79, nan, nan, 765.037],[nan, nan, nan, nan, nan, nan, nan, 763.8852]

Answer 1

你可以像这样循环数组：

nd = np.array( ... )
for i, x in enumerate(list1):
    for y in nd[i]:
        for j in range(len(y)):
            y[j] *= x
print(nd)