List Comprehension Appending Index with Number Range on Lists答案

【问题标题】：List Comprehension Appending Index with Number Range on List of ListsList Comprehension Appending Index with Number Range on Lists
【发布时间】：2020-09-07 04:03:35
【问题描述】：

我正在寻找一种列表理解，即根据列表列表中的索引位置添加一系列数字，同时单独保留第二个索引。

search_keys =  [('1', 'B'), ('1', 'K'), ('1', 'Y')]

期望的结果：

new_search_keys = [('11', 'B'), ('12', 'B'), ('13', 'B'), ('14', 'B'), ('15', 'B')...
                  ...('11', 'K'), ('12', 'K'), ('13', 'K'), ('14', 'K'), ('15', 'K')...
                  ...('11', 'Y'), ('12', 'Y'), ('13', 'Y'), ('14', 'Y'), ('15', 'Y')...]

我的尝试带来了一个 TypeError: 'type' object is not subscriptable:

new_search_keys = [search_keys[i][0] + list(range[1,9]) for i in range(len(search_keys))]

【问题讨论】：

标签： python list indexing list-comprehension

【解决方案1】：

这应该可以解决您的问题：-

new_search_keys = [(search_keys[i][0] +str(j), search_keys[i][1]) for i in range(len(search_keys)) for j in range(1,9)]

输出：-

[('11', 'B'), ('12', 'B'), ('13', 'B'), ('14', 'B'), ('15', 'B'), ('16', 'B'), ('17', 'B'), ('18', 'B'), ('11', 'K'), ('12', 'K'), ('13', 'K'), ('14', 'K'), ('15', 'K'), ('16', 'K'), ('17', 'K'), ('18', 'K'), ('11', 'Y'), ('12', 'Y'), ('13', 'Y'), ('14', 'Y'), ('15', 'Y'), ('16', 'Y'), ('17', 'Y'), ('18', 'Y')]

【讨论】：