从二维列表中删除重复的后续条目

Question

我有以下清单：

p =\
 [(58.5, -4.5),
 (67.5, -4.5),
 (76.5, -4.5),
 (76.5, 4.5),
 (67.5, 4.5),
 (58.5, 4.5),
 (67.5, 4.5),
 (58.5, 4.5),
 (58.5, 13.5),
 (49.5, 13.5),
 (40.5, 13.5),
 (49.5, 13.5),
 (40.5, 13.5),
 (40.5, 22.5),
 (31.5, 22.5),
 (22.5, 22.5),
 (31.5, 22.5),
 (22.5, 22.5),
 (22.5, 31.5),
 (13.5, 31.5),
 (4.5, 31.5),
 (13.5, 31.5),
 (4.5, 31.5),
 (4.5, 40.5),
 (-4.5, 40.5),
 (-4.5, 31.5),
 (-4.5, 22.5),
 (-4.5, 31.5),
 (-4.5, 22.5),
 (-4.5, 13.5),
 (-4.5, 22.5),
 (-4.5, 13.5),
 (-4.5, 4.5),
 (-4.5, 13.5),
 (-4.5, 4.5),
 (-4.5, -4.5),
 (4.5, -4.5),
 (13.5, -4.5),
 (4.5, -4.5),
 (13.5, -4.5),
 (22.5, -4.5),
 (13.5, -4.5),
 (22.5, -4.5),
 (31.5, -4.5),
 (22.5, -4.5),
 (31.5, -4.5),
 (40.5, -4.5),
 (31.5, -4.5),
 (40.5, -4.5),
 (49.5, -4.5),
 (40.5, -4.5),
 (49.5, -4.5),
 (58.5, -4.5),
 (49.5, -4.5),
 (58.5, -4.5)]

如您所见，有一些重复的坐标：

我只保留一个坐标的第一次出现并删除同一坐标的所有后续重复：

在 Python 中有什么聪明的方法可以做到这一点吗？

Answer 1

最简单的方法： list(set(p))

编辑：要保留订单，请执行以下操作： [c for i, c in enumerate(p) if c not in p[:i]]

Answer 2

您可以使用set 过滤重复项（p 是您的问题列表）：

seen = set()
out = []
for coord in p:
    if coord not in seen:
        out.append(coord)
        seen.add(coord)

from pprint import pprint

pprint(out)

打印：

[(58.5, -4.5),
 (67.5, -4.5),
 (76.5, -4.5),
 (76.5, 4.5),
 (67.5, 4.5),
 (58.5, 4.5),
 (58.5, 13.5),
 (49.5, 13.5),
 (40.5, 13.5),
 (40.5, 22.5),
 (31.5, 22.5),
 (22.5, 22.5),
 (22.5, 31.5),
 (13.5, 31.5),
 (4.5, 31.5),
 (4.5, 40.5),
 (-4.5, 40.5),
 (-4.5, 31.5),
 (-4.5, 22.5),
 (-4.5, 13.5),
 (-4.5, 4.5),
 (-4.5, -4.5),
 (4.5, -4.5),
 (13.5, -4.5),
 (22.5, -4.5),
 (31.5, -4.5),
 (40.5, -4.5),
 (49.5, -4.5)]